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yKpoI14uk [10]
2 years ago
8

What happens as the key length increases in an encryption application?

Computers and Technology
1 answer:
pashok25 [27]2 years ago
6 0
<span>The answer is : Increasing the key length of DES would  protect it against brute force attacks.  </span>Brute force is when the attacker tries every key knowing that one will eventually work.  <span>Key length increase proportionally increases the key space,  having a keyspace l</span>arge enough that it takes too much time and money to accomplish a brute force attack.
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Joe, Kate and Jody are members of the same family. Kate is 5 years older than Joe. Jody is 6 years older than Kate . The sum of
mezya [45]

Answer:

5, 10 and 16

Explanation:

The sum of their ages is √961 = 31

If Joe is x years old, the equation that follows is:

x + (x+5) + (x+5+6) = 31

This simplifies to

3x = 31 - 11 - 5 = 15

so x=5

From that you can find

Joe = x = 5

Kate = x+5 = 10

Jody = x+5+6 = 16

5 0
2 years ago
Read 2 more answers
Will mark brainliest if correct. First come, first serve.
VladimirAG [237]

Answer:

Low sampling rate and low bit depth are the right options.

Explanation:

The low sampling rate and low bit depth can ensure less memory consumption. The musician here wants to record some initial ideas for some new song. And she is not concerned about the quality of the audio file she is going to send. And she wishes to send the size of the file that is as small as possible so that it can be quite easily downloaded by her bandmate. She can thus afford a low sampling rate and low bit depth, as the quality is not that important. And a low sampling rate and low bit depth can ensure less memory. Hence, these are the correct options here.

4 0
2 years ago
When a button is selected, the computer processes the code contained in the buttons ____ event procedure?
My name is Ann [436]
The event is called keypress, usually the code is referred to as callback.
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2 years ago
An automobile battery, when connected to a car radio, provides 12.5 V to the radio. When connected to a set of headlights, it pr
ladessa [460]
Base on the question, and in my further computation, the possible answers would be the following and I hope you are satisfied with my answer and feel free to ask for more.

- If you want to determine the Thevenin equivalent voltage and resistance without overloading the battery, then apply some known resistance 

<span><span>RL</span><span>RL</span></span> and measure the output voltage as <span><span>VL</span><span>VL</span></span>. Measure the voltage without a load as <span><span>V<span>OC</span></span><span>V<span>OC</span></span></span>. The voltage divider equation tells us that

<span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span></span>

Solve for <span><span>R<span>TH</span></span><span>R<span>TH</span></span></span>, and you know that <span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span></span>.

6 0
2 years ago
Write a function string middle(string str) that returns a string containing the middle character in str if the length of str is
Katen [24]

Answer:

function getMiddle(s) {

return s.length % 2 ? s.substr(s.length / 2, 1) : s.substr((s.length / 2) - 1, 2);

}

// I/O stuff

document.getElementById("submit").addEventListener("click", function() {

input = document.getElementById("input").value;

document.getElementById("output").innerHTML = getMiddle(input);

});

Explanation:

// >>> is an unsigned right shift bitwise operator. It's equivalent to division by 2, with truncation, as long as the length of the string does not exceed the size of an integer in Javascript.

// About the ~ operator, let's rather start with the expression n & 1. This will tell you whether an integer n is odd (it's similar to a logical and, but comparing all of the bits of two numbers). The expression returns 1 if an integer is odd. It returns 0 if an integer is even.

// If n & 1 is even, the expression returns 0.

// If n & 1 is odd, the expression returns 1.

// ~n & 1 inverts those two results, providing 0 if the length of the string is odd, and 1 if the length of the sting is even. The ~ operator inverts all of the bits in an integer, so 0 would become -1, 1 would become -2, and so on (the leading bit is always the sign).

// Then you add one, and you get 0+1 (1) characters if the length of the string is odd, or 1+1 (2) characters if the length of the string is even.

6 0
2 years ago
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