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2 years ago

What happens as the key length increases in an encryption application?

1 answer:

6 0

<span>The answer is : Increasing the key length of DES would protect it against brute force attacks. </span>Brute force is when the attacker tries every key knowing that one will eventually work. <span>Key length increase proportionally increases the key space, having a keyspace l</span>arge enough that it takes too much time and money to accomplish a brute force attack.

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RFID tags are used in secure environments primarily due to the fact they are impossible to counterfeit.

denis23 [38]

Answer: True

Explanation:

Yes, the given statement is true that the RFID tags are basically used in the secure system because it is impossible to counterfeit.

RFID basically stand for the radio frequency identification that provide a method to retrieve the data or information quickly from the system. It basically used as radio wave technology in which we can easily track the objects and people by using proper programmed data.

The tag is basically placed in the object for unique identification. There are basically two types of tags in the RFID that is active and passive.

4 0

1 year ago

What is the output of 1101 x 10 == 11000 + 10?

Marta_Voda [28]

== is an operator that returns a boolean if both operand are equal.

1101 * 10 is 11010

11000 + 10 is 11010

11010 == 11010

Thus the output would be True.

5 0

2 years ago

Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers represent color by combinin

Dmitry_Shevchenko [17]

Answer:

Follows are the code to this question:

#include<iostream>//defining header file

using namespace std;// use package

int main()//main method

{

int red,green,blue,x;//declaring integer variable

cin>> red >>green>>blue;//use input method to input value

if(red<green && red<blue)//defining if block that check red value is greater then green and blue

{

x = red;//use x variable to store red value

}

else if(green<blue)//defining else if block that check green value greater then blue

{

x= green; //use x variable to store green value

}

else//defining else block

{

x=blue;//use x variable to store blue value

}

red -= x;//subtract input integer value from x

green -=x; //subtract input integer value from x

blue -= x;//subtract input integer value from x

cout<<red<<" "<<green<<" "<<blue;//print value

return 0;

}

Output:

130 50 130

80 0 80

Explanation:

In the given code, inside the main method, four integers "red, green, blue, and x" are defined, in which "red, green, and blue" is used for input the value from the user end. In the next step, a conditional statement is used, in the if block, it checks red variable value is greater than then "green and blue" variable. If the condition is true, it will store red variable value in "x", otherwise, it will goto else if block.

In this block, it checks the green variable value greater than the blue variable value. if the condition is true it will store the green variable value in x variable.
In the next step, else block is defined, that store blue variable value in x variable, at the last step input variable, is used that subtracts the value from x and print its value.

5 0

2 years ago

Select the correct answer. Andy wants to become a multimedia producer. Which degree can help him achieve this goal? A. bachelor’

tatuchka [14]

Answer:

C. bachelor’s degree in filmmaking

Explanation:

Because Andy wants to become a multimedia producer, the degree that would best help him achieve his goal is a bachelor's degree in filmmaking.

Multimedia has to do with both audio, video and graphics or animations because it encompasses multiple media files.

Filmmaking has to do with the various forms of making and producing films. Filmmaking has to do with multiple media (multimedia) and it would help him achieve his goal.

7 0

1 year ago

Consider the following skeletal C program: void fun1(void); /* prototype */ void fun2(void); /* prototype */ void fun3(void); /*

natita [175]

Answer:

Check the explanation

Explanation:

a) main calls fun1; fun1 calls fun2; fun2 calls fun3

fun3() d, e, f

fun2() c, d, e

fun1() b, c, d

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun3().

In fun3(), the local variables "d, e, f" of fun3() will be visible

variable "c" of fun2() will be visible

variable "b" of fun1() will be visible

variable "a" of main() will be visible

b) main calls fun1; fun1 calls fun3

fun3() d, e, f

fun1() b, c, d

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun3().

In fun3(), the local variables "d, e, f" of fun3() will be visible

variable "b, c" of fun1() will be visible

variable "a" of main() will be visible

c) main calls fun2; fun2 calls fun3; fun3 calls fun1

fun1() b, c, d

fun3() d, e, f

fun2() c, d, e

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun1().

In fun1(), the local variables "b, c, d" of fun1() will be visible

variable "e, f" of fun3() will be visible

variable "a" of main() will be visible

d) main calls fun1; fun1 calls fun3; fun3 calls fun2

fun2() c, d, e

fun3() d, e, f

fun1() b, c, d,

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun2().

In fun2(), the local variables "c, d, e" of fun2() will be visible

variable "f" of fun3() will be visible

variable "b" of fun1() will be visible

variable "a" of main() will be visible

The last function called will comprise of all its local variables and the variables other than its local variables from all its preceding function calls till the main function.

8 0

1 year ago