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riadik2000 [5.3K]
2 years ago
5

A population of endangered birds decreases by 3% each year.

Mathematics
2 answers:
Lana71 [14]2 years ago
8 0
Since the number of bird decreases 3% per year then for year 1 there will be 29 100 birds left. This value is 97% of 30000. From this the number of birds for year 1 is N = 30000(1-0.03)

A. N = 30,000(1-0.03)^{2}

B. To solve this we use the equation we established in letter A. We get the answer by substituting T with 20. N = 16,000. <span />
posledela2 years ago
4 0

Answer: a) The required equation is,

N=30000(0.97)^T

b) The approximately population of the birds after 20 years is 16314.

Step-by-step explanation:

a) Since, the initial population, P = 30,000

The rate of increasing, r = 3% per year,

Hence, the population of birds after T years,

N=P(1-\frac{r}{100})^T

\implies N = 30000(1-\frac{3}{100})^T

\implies N = 30000(1-0.03)^T

\implies N=30000(0.97)^T

Which is the required equation.

b) Now, for T = 20 years,

The population of birds,

N(20)=30000(0.97)^{20}=30000\times 0.543794342927=16313.8302878\approx 16314

⇒ The approximately population of the birds after 20 years is 54183.

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