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weqwewe [10]
2 years ago
9

Consider a single spin on the spinner shown below. Which events are mutually exclusive? Check all that apply.

Mathematics
2 answers:
julia-pushkina [17]2 years ago
7 0

Answer:

Options A, B and E represent mutually exclusive events.

Step-by-step explanation:

Two events are mutually exclusive that can not happen at a same time.

Now let us look at our options and find which statements represent mutually exclusive events.

A. We can see that landing on an unshaded portion and landing on 2 are mutually exclusive events as unshaded portion contains 3 and 4 and 2 lies on shaded portion.

B. Landing on a shaded portion and landing on 3 is also mutually exclusive as 3 lies on unshaded portion.

C. Landing on a shaded portion and landing on an even number can happen at the same time as 2 is an even number and it lies on shaded portion.

D. Landing on an unshaded portion and landing on a number greater than 3 can happen at the same time as 4 in greater than 3 and it lies on unshaded portion.

E. Landing on a shaded portion and landing on an unshaded portion  are mutually exclusive events as spinner can be either in shaded portion or in unshaded portion.

Therefore, Options A, B and E are our correct choices.

Softa [21]2 years ago
5 0
The correct answers are:
<span>landing on an unshaded portion and landing on 2
landing on a shaded portion and landing on 3</span><span>and landing on a shaded portion and landing on an unshaded portion</span>
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(x + b/2a)² = -c/a + (b/2a)² =  -c / a + b²/4a² = (-4ac+ b²)/4a²

(x + b/2a)² =  (-4ac+ b²)/4a²

  • square root both sides

√{(x + b/2a)²} = √{(-4ac+ b²)/4a²}

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x + b/2a  =  √( b²-4ac) / 2a

  • subtract b/2a from both sides

x + b/2a -b/2a  =  {√( b²-4ac) / 2a } -b/2a

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  • the l.c.m is the same

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Which summation represents the total number of pennies on the chessboard?
Charra [1.4K]

Answer:

  • First option of the figure:

                                                      \sum_{n=1}^{64}1.2^{n-1}

Explanation:

Assume that the complete question includes the following description of how the pennies are placed on the chessboard:

"If a chessboard (8×8) were to have pennies placed on each square such that 1 penny was placed on the first square, 2 on the second, 4 on the third, and so on (doubling the number of pennies on each subsequent square), how many pennies would be on the chessboard when finished?"

From that you can write the first terms of the sequence that represent such description

Square           number of pennies         power form

   1                                 1                           1 × 2⁰

  2                                2                           1 × 2¹

  3                                4                           1 × 2²

  4                                8                          1 × 2³

  5                               16                          1 × 2⁴

  n                                                             1 × 2ⁿ⁻¹

  64                                                           1 × 2⁶³

Hence, you to have the total number of pennies you have to sum the number of pennies on every square of the chessboard, which will lead to :

1 × 2⁰ +  1 × 2¹ + 1 × 2² +  1 × 2³ +  1 × 2⁴ + ...  1 × 2ⁿ⁻¹ up to n = 64 or n - 1 = 63.

That is the sum from n = 1 to 64 - 1 of 1 × 2ⁿ⁻¹, which using summation form is the first option on the picture.

                 \sum_{n=1}^{64}1.2^{n-1}

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2 years ago
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