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madreJ [45]
2 years ago
11

What are the vertex and x-intercepts of the graph of the function given below?

Mathematics
2 answers:
Sloan [31]2 years ago
8 0

Answer:

D. Vertex: (1, –49); x-intercepts: (8, 0) and (–6, 0)

madreJ [45]2 years ago
5 0
VERTEX
To determine the vertex (coordinate x) of parabola y = ax² + bx + c, use this following formula
x vertex = -\dfrac{b}{2a}

y = x² - 2x - 48
a = 1, b = -2, c = -48
plug in the numbers
x vertex = -\dfrac{b}{2a}
x vertex =  -\dfrac{(-2)}{2(1)}
x vertex =  \dfrac{2}{2}
x vertex = 1

To find y vertex, substitute the value of x vertex to the parabola equation
y = x² - 2x - 48
y = 1² - 2(1) - 48
y = 1 - 2 - 48
y = -49

The vertex is (1, -49)

X-INTERCEPT
x-intercept located in x axis, that means y = 0. Substitute y = 0 to the parabola equation
x² - 2x - 48 = y
x² - 2x - 48 = 0
(x - 8)(x + 6) = 0
x = 8 or x = -6
The x-intercepts are (8,0) and (-6,0)

The answer is first option
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Erin built a wooden box to hold hay on her farm. Hay costs $14dollar sign, 14 per cubic meter. How much will it cost to complete
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Here is the complete question.

Erin built a wooden box to hold hay on her farm.The box is 3 \text { m}3 m3, start text, space, m, end text long, 1 \text { m}1 m1, start text, space, m, end text wide, and 1 \text { m}1 m1, start text, space, m, end text high.Hay costs $14dollar sign, 14 per cubic meter. How much will it cost to completely fill the box with hay?

Answer:

it cost  $42 to completely fill the box with hay

Step-by-step explanation:

Given that :

The length of the wooden box = 3m ; the width of the box = 1m and the height of the box = 1 m; we can easily determine the volume of the rectangular wooden box;

We all know it would assume the shape of a rectangular prism and it's volume = L  × W × H

Thus; the volume of the box = . 3 m × 1 m × 1 m = 3 m³

However, the question proceeds by stating it that the wooden box cost $14 per cubic meter;

So , if 1 cubic meter = $14;

three cubic meters = $14 × 3  = $42

Hence;  it cost  $42 to completely fill the box with hay

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2 years ago
A sample of 1714 cultures from individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiot
Damm [24]

Answer:

a) p represent the real population proportion of people who showed partial or complete resistance to the antibiotic

b) \hat p=\frac{973}{1714}=0.568 represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

c) We are confident (95%) that the true proportion of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic is between 54.5% to 59.1%.  

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

Description in words of the parameter p

p represent the real population proportion of people who showed partial or complete resistance to the antibiotic

\hat p represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

n=1714 is the sample size required

z_{\alpha/2} represent the critical value for the margin of error

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Part b

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

\hat p=\frac{973}{1714}=0.568 represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

Part c

The confidence interval for a proportion is given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.568 - 1.96 \sqrt{\frac{0.568(1-0.568)}{1714}}=0.545

0.568 + 1.96 \sqrt{\frac{0.56(1-0.56)}{1714}}=0.591

And the 95% confidence interval would be given (0.545;0.591).

We are confident that about 54.5% to 59.1% of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic.  

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