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Solnce55 [7]
2 years ago
9

A deck of playing cards has four suits, with thirteen cards in each suit consisting of the numbers 2 through 10, a jack, a queen

, a king, and an ace. The four suits are hearts, diamonds, spades, and clubs. A hand of five cards will be chosen at random. Which statements are true? Check all that apply.
The total possible outcomes can be found using 52C5.

The total possible outcomes can be found using 52P5.

The probability of choosing two diamonds and three hearts is 0.089.

The probability of choosing five spades is roughly 0.05

The probability of choosing five clubs is roughly 0.0005.
Mathematics
2 answers:
Rudik [331]2 years ago
6 0
A. True. There are 52 cards total and you only pick 5. Order doesn't matter.

-------------------------------------------

B. False. Order doesn't matter so you use a combination (instead of a permutation) as choice A shows.

-------------------------------------------

C. False. The answer is roughly 0.000858 as shown by the calculation below

(13/52)*(12/51)*(13/50)*(12/49)*(11/48) = 0.000858

-------------------------------------------

D. False. See calculation below

(13/52)*(12/51)*(11/50)*(10/49)*(9/48) = 0.000495

-------------------------------------------

E. True. See calculation below

(13/52)*(12/51)*(11/50)*(10/49)*(9/48) = 0.000495
this value rounds to roughly 0.0005
adoni [48]2 years ago
3 0

Answer:A & E

Step-by-step explanation:

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Quincy, Ralph, Samantha and Teresa all joined a summer reading program. Quincy read five more books than Ralph did. Ralph read h
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Answer:

Quincy read 9 books.

Step-by-step explanation:

Work backwards. Samantha read three less books than Teresa (11-3=8). Ralph read half as many books as Samantha (8/2 = 4). Quincy read five more books than Ralph (4 + 5 = 9).

5 0
2 years ago
1. There are 125 juniors at the high school.How many ways can they elect a
valentinak56 [21]

Answer: 1.   1,906,500

 2.   840

Step-by-step explanation:

1. Given: There are 125 juniors at the high school.

Total positions = 3    [president,vice president, and secretary]

Then, Number of ways to elect a  president,vice president, and secretary( which is in order) out of  125 juniors = ^{125}P_{3}=\dfrac{125!}{(125-3)!}  [Using permutations]

=\dfrac{125!}{122!}\\\\=\dfrac{125\times124\times123\times122!!}{122!}\\\\=125\times124\times123\\\\=1906500

Hence, Required ways =1906500

(2) Given word : "RHOMBUS"

Total letters= 7

By permutation, the umber of 4-letter arrangements = ^7P_4=\dfrac{7!}{(7-4)!}=\dfrac{7!}{3!}

=\dfrac{7\times6\times5\times4\times3!}{3!}\\\\= 7\times6\times5\times4\\\\=840

Hence, required ways = 840

7 0
2 years ago
22. What is the percent of increase for a population<br> that changed from 438,000 to 561,000?
ra1l [238]

Answer: 28.08%

Step-by-step explanation: To find the percent increase, we divide the amount of change by the original number.

The amount of change is the difference between the two numbers which in this case is 561,000 - 438,000 and the original number is 438,000.

561,000 - 438,000 is 123,000 so we are left with 123,000 divided by 438,000 which is 0<em>.</em>2808. Finally, since our problem is asking us for a percent, we write 0<em>.</em>2808 as a percent by moving the decimal point two places to the right to get 28.08%.

So when the population changes from 438,000 to 561,000, it has increased by 28.08%.

5 0
2 years ago
A poll stated that 32% of those polled think the economy is getting worse. An economist wanted to check this claim so she survey
zysi [14]

Answer:

z=\frac{0.30 -0.32}{\sqrt{\frac{0.32(1-0.32)}{750}}}=-1.174  

The p value for this case would be given by:

p_v =2*P(z  

For this case since the p value is higher than the significance level given we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not significantly different from 0.32 or 32 %

Step-by-step explanation:

Information given

n=750 represent the random sample taken

\hat p=0.30 estimated proportion of  people who  thought the economy is getting worse

p_o=0.32 is the value that we want to verify

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to check if the true proportion of interest is equal to 0.32 or not.:  

Null hypothesis:p=0.32  

Alternative hypothesis:p \neq 0.32  

The statistic would be given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.30 -0.32}{\sqrt{\frac{0.32(1-0.32)}{750}}}=-1.174  

The p value for this case would be given by:

p_v =2*P(z  

For this case since the p value is higher than the significance level given we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not significantly different from 0.32 or 32 %

8 0
2 years ago
20 boxes of apples have been delivered to a restaurant. The number of apples in each box is counted. Complete the table below an
blsea [12.9K]

Answer:

30 apples

Step-by-step explanation:

600 is the total number of apples (adding all numbers in the apples*frequency column). Dividing this by 20, the number of boxes, we get 30 apples as the mean number in a box.

3 0
2 years ago
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