<span>During process 1→3→6, the temperature of the gas decreases slowly during process , the temperature of the gas rapidly decreases and then increases increases and then decreases remains constant. Hence, in the first step, the temperature of gas decreases slowly, then decreases rapidly, then it increases and finally the decreases becomes constant.</span>
Answer:
I might be wrong but im guessing 600
Explanation:
Since there is one molecule of glucose used per 6 molecules of carbon dioxide released, if you have 100 molecules of glucose, then you multiply the carbon dioxide by 100 which is 600. Thats what I would say but I might be wrong.
It is called the transition state species. They are a bit of a hybrid, or a halfway point between the structure of the reactants' structures and products' structures. Bonds in the transition state can be partially formed and are represented by a dotted line.
Answer:
D. 0.60
Explanation:
If the population is in Hardy-Weinberg equilibrium, the genotypic frequencies are:
- freq AA = p²
- freq Aa = 2pq
- freq aa = q²
<em>p</em> is the frequency of the Rh positive allele (A) and <em>q</em> is the frequency of the Rh-negative allele (a).
If 84% of the population is Rh-positive, then 16% is Rh-negative and has the genotype <em>aa</em>. Therefore:
q² = 0.16
q = √0.16
q=0.4
And because p+q=1,
p = 1 - 0.4
p = 0.6
The frequency of the Rh-positive allele is 0.6
The P waves vibrate very quickly out from the epicenter first in all directions, in a circular way passing the station. The S waves then vibrate out from the epicenter a few seconds later and cause the sideways shaking of the land as they pass the station. The P wave then reflects off the core of the Earth and bounces back past the station, followed by the S wave a few seconds later because both waves reflect off the earths core back to the epicenter.
