2 years ago

Seventy percent of a town's population voted in an election. if 1,589 people voted, how many people are in the town?

Mathematics

1 answer:

Goryan [66]2 years ago

3 0

Assume X represent the all people in the town, so

100%=X

if 70%=1,589 =>what about 100% which represent the entire population X

70%=1,589 and 100%=x so X=(100%*1,589)/70 = 2,270

so the town people are =2,270

(If you have more complex answer you can find me at essaywritingpool.com)

You might be interested in

Ms. Li gave her students a quiz that was supposed to take 6 minutes to complete. She asked her students to record the amount of

Kamila [148]

B. I think it is b because i feel like a dot plot would be helpful

3 0

2 years ago

I go to the store and buy instant noodles for 7.75 pesos, can of sardines for 16.00 pesos and 2 sachets of coffee for 12.25 peso

Elena-2011 [213]

Answer:

36.00 pesos or $1.73

Step-by-step explanation:

plz give brainliest

5 0

2 years ago

Zane and Matt are both keen runners. Zane takes 4 minutes to jog around a running track and Matt takes 5 minutes. They start at

Sergio [31]

I believe that the correct answer to this question is B. because matt took more than 5 minutes .

3 0

2 years ago

The scatterplot shows the sales, in dollars, of snow cones in relation to the outside temperature, in degrees Celsius. According

maksim [4K]

B) it is 450 dollars

7 0

2 years ago

Read 2 more answers

Model Exponential Growth Question :A sample of bacteria is growing at a continuously compounding rate. The sample triples in 10

Iteru [2.4K]

Answer:

The number of bacteria $B$ after $d$ days is given by

$B = B_0 (3)^{\frac{1}{10} d}$

where $B_0$ is the initial number of bacteria.

Step-by-step explanation:

The number of bacteria $B$ in the sample triples every 10 days, this means after the first 10th day, the number of bacteria is

$B = B_0 *3,$

where $B_0$ is the initial number of bacteria in the sample.

After the 2nd 10th days, the number of bacteria is

$B = (B_0 *3)*3$

after the 3rd day,

$B =( B_0 *3*3)*3$

and so on.

Thus, the formula we get for the number of bacteria after the <em>n</em>th 10-days is

$B = B_0 (3)^n$

where $n$ is is the <em>n</em>th 10-days.

Since, $n$ is 10 days, we have

$d =10n$

$n =\dfrac{1}{10}$

Substituting that into $B = B_0 (3)^n$ , we get:

$\boxed{ B = B_0 (3)^{\frac{1}{10} d}}$

8 0

2 years ago