6i/ (1+i)
multiply by the complex conjugate (1-i)/(1-i)
6i/(1+i) * (1-i)/(1-i)
6i* (1-i) = 6i - 6i^2 = 6i - 6(-1) = 6i +6
(1+i)*(1-i)= 1-i +i -i^2 = 1 -i+i -(-1) = 1+1=2
(6+6i)/2
3+3i
Answer: 3+3i
Let the number of reserved tickets = x
Let the number of lawn seats = y
Constraint functions:
Maximum capacity means 
For concert to be held 
means 
Objective functions :
Maximum profit equation p = 65x +40y
Intersection points :
(10000,10000) (20000,0)(2500,2500)(5000,0)
p at (10000,10000) = 65(10000) + 40(10000) = $1050000
p at (20000,0) = 65(20000) + 40(0) = $1300000
p at (2500,2500) = 65(2500) + 40(2500) = $262500
p at (5000,0) = 65(5000) + 40(0) = $325000
Hence maximum profit occurs when all 20000 reserved seats are sold and the profit is $1300000
Please find attached the graph of it.
Nearest hundred thousand: 100,000
Nearest ten thousand: 130,000
Nearest thousand: 127,000
The closest rounded amount to the actual attendance is the nearest thousand, 127,000.
Well, the data you gave us is confusing, so i'm just going to say that it is the lowest percentage possible 39.1%, because by the choices given, it shouldn't be lower than that
hope this helps