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Olin [163]
2 years ago
4

A caterpillar eats 1400% of its birth mass in one day. The caterpillars birth mass is m grams. Which of the following expression

s could represent the amount, in grams, the caterpiller eats in one day?
Mathematics
2 answers:
AlekseyPX2 years ago
4 0

For this case we have the following variable:

m: The caterpillars birth mass

We know that a caterpillar eats 1400% of its birth mass in one day.

We must then model this problem through a mathematical expression.

We have then:

\frac{1400}{100}m

Rewriting we have:

14m

Answer:

The following expression could represent the amount, in grams, the caterpiller eats in one day:

14m

AlladinOne [14]2 years ago
4 0

The answer to this is 14m and if it is an option 1400/100 m

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Step-by-step explanation:

Solution:

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1st : 0.25*\sqrt{15}\\\\2nd: 0.25*\sqrt{15} + 0.25*\sqrt{15*\frac{7}{8} } + 0.25*\sqrt{15*\frac{7}{8} } = 0.25*\sqrt{15} + 0.5*\sqrt{15*\frac{7}{8} }\\\\3rd: 0.25*\sqrt{15} + 0.5*\sqrt{15*\frac{7}{8} } + 2*0.25*\sqrt{15*(\frac{7}{8} })^2\\\\= 0.25*\sqrt{15} + 0.5*\sqrt{15*\frac{7}{8} } + 0.5*\sqrt{15*(\frac{7}{8} })^2\\\\4th: 0.25*\sqrt{15} + 0.5*\sqrt{15*\frac{7}{8} } + 0.5*\sqrt{15*(\frac{7}{8} })^2 + 2*0.25*\sqrt{15*(\frac{7}{8} })^3 \\\\

= 0.25*\sqrt{15} + 0.5*\sqrt{15*\frac{7}{8} } + 0.5*\sqrt{15*(\frac{7}{8} })^2 + 0.5*\sqrt{15*(\frac{7}{8} })^3

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                                  Total Time = 4.51 s

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