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MrRa [10]
2 years ago
10

Which answers are examples of the Law of Syllogism? Select each correct answer. If two numbers are even then their sum is even.

Ten and 12 are even numbers. The sum of 10 and 12 is even. If the lengths of the sides of a triangle are equal, the triangle is an equilateral triangle. If a triangle is equilateral, each angle of the triangle measures 60°. Therefore, if the lengths of the sides of a triangle are equal, each angle of the triangle measures 60°. If the dog belongs to Mike, the dog is a beagle. Jake is Mike’s dog. Therefore, Jake is a beagle. If a student sells 10 boxes of candy, the student will get to go on the class field trip. If there is a class field trip, it will be to the aquarium. Therefore, if a student sells 10 boxes of candy, the student will get to go to the aquarium.
Mathematics
2 answers:
maxonik [38]2 years ago
8 0
10
Box’s will be sold on the worlds biggest bost
lapo4ka [179]2 years ago
3 0

A syllogism is a form of logical reasoning that joins two or more premises to arrive at a conclusion. They include a major premise and a minor premise. In comparison, the law of detachment is when there are two premises that are accepted as true and are used to reach a conclusion (if p, then q).

The bolded statments show the law of syllogism (the answer to the question), while the unbolded statements are examples of the law of detachment.

<u>Law of syllogism</u>

If the lengths of the sides of a triangle are equal, the triangle is an equilateral triangle. If a triangle is equilateral, each angle of the triangle measures 60°. Therefore, if the lengths of the sides of a triangle are equal, each angle of the triangle measures 60°.

If a student sells 10 boxes of candy, the student will get to go on the class field trip. If there is a class field trip, it will be to the aquarium. Therefore, if a student sells 10 boxes of candy, the student will get to go to the aquarium.

<u>Law of detachment</u>

If two numbers are even then their sum is even. Ten and 12 are even numbers. The sum of 10 and 12 is even.

If the dog belongs to Mike, the dog is a beagle. Jake is Mike’s dog. Therefore, Jake is a beagle.

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The <em>t</em>-value used for the 95% confidence interval of paired data is 2.776.

Step-by-step explanation:

The confidence interval formula for mean difference for a paired data is as follows:

CI=\bar x_{d}\pm t_{\alpha/2, (n-1)}\times \frac{s_{d}}{\sqrt{n}}

Here,

\bar x_{d} = sample mean of the difference,

s_{d} = sample standard deviation of the difference,

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t_{\alpha/2, (n-1)} = critical value of <em>t</em>

(<em>n</em> - 1) = degrees of freedom

The information provided is:

<em>n</em> = 5

Confidence level = 95%

The critical value of <em>t</em> is:

t_{\alpha/2, (n-1)}=t_{0.05/2, (5-1)}

               =t_{0.025, 4}

               =2.776

*Use a <em>t</em>-table for the critical value of <em>t</em>.

Thus, the <em>t</em>-value used for the 95% confidence interval of paired data is 2.776.

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Answer:

The answer is below

Step-by-step explanation:

A cell tower is located 3 miles east and 4 miles north of the center of a small town. The cell tower has a coverage radius of 3 miles.

a) Start by drawing a diagram of this situation. Your diagram might include a coordinate plane, the cell tower, and a circle representing the cell tower's coverage boundary.

a) A house is located 5 miles north of the center of the town and is to the east of the cell tower. If the house lies on the boundary of the cell tower's coverage, how far east of the center of the town is the house?

Answer:

Let the center of the town represent the origin (0,0). Also 1 unit = 1 mile. Since the cell tower is located 3 miles east and 4 miles north of the center of a small town, it is represented by A(3, 4)

The cell tower has a coverage of radius 3 miles. This can be represented by a circle with equation:

(x - a)² + (y - b)² = r². where (a,b) is the center of the circle and r is the radius. Hence:

(x - 3)² + (y - 4)² = 3²

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The diagram is drawn using geogebra.

b) The house is 5 miles north. It can be represented by y = 5 line.

To find the distance east of the house we have to substitute y = 5 and solve for x, hence:

(x - 3)² + (y - 4)² = 9

(x - 3)² + (5 - 4)² = 9

(x - 3)² + 1 = 9

(x - 3)² = 8

(x - 3) = √8

x - 3 = ±2.83

x = 3 ± 2.83

x = 5.83 or 1.83

Since it is to the east to the cell tower, hence x = 5.83.

Therefore the house is located 5.83 miles to the east of the cell tower

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