If we let
x as the distance traveled by the boat
y as the distance between the boat and the lighthouse.
Then, we have:
tan 18°33' = 200 / (x + y)
and
tan 51°33' = 200 / y
Solving for y in the second equation:
y = 200 / tan 51°33'
Rearranging the first equation and substituting y
x = 200 / tan 18°33' - 200 / tan 55°33'
x = 458.81 ft
Therefore, the boat traveled 458.81 ft before it stopped.
