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2 years ago

Which expression gives the distance between the points (5,1) and (9, -6)

Mathematics

2 answers:

Aleksandr [31]2 years ago

6 0

Answer:

The expression

D = √(x2-x1)²+(y2-y1)

Distance between the two point is 8.06

Step-by-step explanation:

Given two points in space (x1,y1) and (x2,y2). The distance between this two points is calculated using the expression

D = √(x2-x1)²+(y2-y1)²

Given two points, the expression which gives the distance between the two points is described using the above formula.

Given the points (5,1) and (9, -6)

x1 = 5, y1= 1, x2 = 9, y2 = -6

D = √(9-5)²+(-6-1)²

D = √4²+(-7)²

D = √16+49

D = √65

D = 8.06

mel-nik [20]2 years ago

3 0

I believe you do
$x^{2} - x
 /y^{2} - y$

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Find each measure for the given set of data: 11, 13, 17, 20, 22, 25, 27, 31, 31, 33, Mean= Median= Range= interquartile range= I

Tresset [83]

Answer:

Mean=23

Median =23.5

Range=22

Interquartile range = 14

Step-by-step explanation:

Given set of data

11,13,17,20,22,25,27,31,31,33

Mean $=\frac{11+13+17+20+22+25+27+31+31+33}{10}$

$=\frac{230}{10}$

=23

The $(\frac{n}{2})$ th term= the 5th term

=22

The $(\frac{n}{2}+1)^{th}$ term = The $6^{th$ term

= 25

The median = $\frac{22+25}{2}$

=23.5

Range = Highest term - lowest term

=33- 11

=22

Here lower half {11,13,17,20,22}

The middle number of lower half is first quartile.

Q₁ = 17

And lower half is{25,27,31,31,33}

The middle number of upper half is third quartile.

Q₃=31

Interquartile Range =Q₃-Q₁

=31-17

=14

8 0

2 years ago

In 2003, the Accreditation Council for Graduate Medical Education (ACGME) implemented new rules limiting work hours for all resi

Alborosie

Answer:

80.67 hours

Step-by-step explanation:

Data provided in the question:

The number of weekly hours worked :

78 85 82 79 77 82 81 82 81 81 82 78

total number of observations = 12

Now,

Mean = (Sum of all the data values) ÷ (Total number of data values)

Mean = ( 78 + 85 + 82 + 79 + 77 + 82 + 81 + 82 + 81 + 81 + 82 + 78 ) ÷ 12

Mean = 968 ÷ 12

or Mean = 80.67 hours

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2 years ago

The following curve passes through (3,1). Use the local linearization of the curve to find the approximate value of y at x=2.8.

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d/dx (2 x^2 y + y = 2x + 13) 4xy + 2x^2 y' + y' = 2 4xy + y'(2x^2 + 1) = 2 y' = (2- 4xy)/(2x^2 +1)

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2 years ago

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write an algebraic expression to model each situation. you have a summer job at a car wash. you earn $8.50 per hour and are expe

dybincka [34]

So we know $8.50 per hour
One-time fee of $15 for uniform
x hours per week

y=8.5x-15

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2 years ago

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Michael arthur deported $2,900 in a new regular savings account that earns 5.5 percent interest compounded semiannually he made

il63 [147K]

Answer:

The amount in the account is $3062.4 (Approx) and compound interest is $162.4 .

Step-by-step explanation:

Formula for compounded semiannually

$Amount = P(1 + \frac{r}{2} )^{2t}$

Where P is the principle , r is the rate in decimal form and t is the time.

As given

Michael arthur deported $2,900 in a new regular savings account that earns 5.5 percent interest .

Here

Principle = $2,900

5.5% is written in the decimal form.

$= \frac{5.5}{100}$

= 0.055

Time = 1 year

Put in the formula

$Amount = 2900\times (1 + \frac{0.055}{2} )^{2\times 1}$

$Amount = 2900\times (1 + 0.0275 )^{2\times 1}$

$Amount = 2900\times (1.0275)^{2}$

$Amount = 2900\times 1.056\ (Approx)$

Amount = $ 3062.4 (Approx)

Thus the amount after 1 years is $3062.4 (Approx) .

Now find out the compound interest .

Amount = Principle + Compound interest

Here

Amount = $ 3062.4

Principle = $2,900

Put in the above

$3062.4 = $2,900 + Compound interest

Compound interest = $3062.4 - $2,900

Compound interest = $162.4

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2 years ago