Step-by-step explanation:
A leap year occurs every 4th year.
So, 1875 - 1700 = 175
Now let us divide 175 by 4
So, 43 leap years occur between the years 1700 and 1875.
A café sold 1,400 beverages in one month. If 60% of those beverages were coffee, how many coffees did the café sell in the month
2 answers:
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<u>Given</u>:
Let x represents the radius of the cylinder.
Given that the height of the cylinder is twice the radius of its base.
The height of the cylinder is 2x.
We need to determine the volume of the cylinder.
<u>Volume of the cylinder:</u>
The volume of the cylinder can be determined using the formula,
Substituting r = x and h = 2x, we get;
Simplifying, we get;
Thus, the expression that represents the volume of the cylinder is 2πx³ cubic units.
Hence, Option b is the correct answer.
Answer:
(1). y = x ~ Exp (1/3).
(2). Check attachment.
(3). EY = 3(1 - e^-2).
(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.
Step-by-step explanation:
Kindly check the attachment to aid in understanding the solution to the question.
So, from the question, we given the following parameters or information or data;
(A). The probability in which attempt to establish a video call via some social media app may fail with = 0.1.
(B). " If connection is established and if no connection failure occurs thereafter, then the duration of a typical video call in minutes is an exponential random variable X with E[X] = 3. "
(C). "due to an unfortunate bug in the app all calls are disconnected after 6 minutes. Let random variable Y denote the overall call duration (i.e., Y = 0 in case of failure to connect, Y = 6 when a call gets disconnected due to the bug, and Y = X otherwise.)."
(1). Hence, for FY(y) = y = x ~ Exp (1/3) for the condition that zero is equal to y = x < 6.
(2). Check attachment.
(3). EY = 3(1 - e^-2).
(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.
The condition to follow in order to solve this question is that y = 0 if x ≤ 0, y = x if 0 ≤ x ≤ 6 and y = 6 if x ≥ 6.
