A company is planning to hire 12 new employees a simulation is run to determine 12 random birthdays using numbers to represent t
2 answers:
You might be interested in
When the ball will hit the ground, the height will be zero. So we need to replace 
with 0 in our equation, and solve for 
:
To solve this equation we are going to use the quadratic formula:
.
From our height equation, we can infer that
, 
, and 
. So lets replace those values in our quadratic formula to find
or 
or 
Since time cannot be negative, is the solution of our equation.
We can conclude that the ball will hit the ground after 2.71 seconds.
To solve this equation we are going to use the quadratic formula:
From our height equation, we can infer that
Since time cannot be negative,
We can conclude that the ball will hit the ground after 2.71 seconds.
Answer:
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given first random sample size n₁ = 500</em>
Given Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer.
<em>First sample proportion </em>
<em> </em>
<em>Given second sample size n₂ = 700</em>
<em>Given a sample of 700 men (unrelated to the women) ages 18-29 found that 133 men said that they had the most say when purchasing a computer.</em>
<em>second sample proportion </em>
<em> </em>
<em>Level of significance = α = 0.05</em>
<em>critical value = 1.96</em>
<u><em>Step(ii)</em></u><em>:-</em>
<em>Null hypothesis : H₀: There is no significance difference between these proportions</em>
<em>Alternative Hypothesis :H₁: There is significance difference between these proportions</em>
<em>Test statistic </em>
<em></em><em></em>
<em>where </em>
<em> </em><em></em>
<em> Q = 1 - P = 1 - 0.165 = 0.835</em>
<em></em><em></em>
<em>Z = -2.76</em>
<em>|Z| = |-2.76| = 2.76 > 1.96 at 0.05 level of significance</em>
<em>Null hypothesis is rejected at 0.05 level of significance</em>
<em>Alternative hypothesis is accepted at 0.05 level of significance</em>
<u><em>Conclusion:</em></u><em>-</em>
<em>There is there is a difference between these proportions at α = 0.05</em>
<h2>Answer with explanation:</h2>
To write an inequality and show on a number line all numbers: greater than (−3) but less than or equal to 3
Let n be the number, then -3 < n ≤3 .
On number line we mark open circle at -3 (since it has a strictly less than sign) and a closed circle at 3 (since it has a less than and equal to sign) .
To the required inequality that shows all the numbers greater than (−3) but less than or equal to 3 : -3 < n ≤3 and the number line is represented below.