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lesya692 [45]
2 years ago
8

Find the velocity in meters per second of a baseball thrown 38m from third base in 1.7s

Mathematics
1 answer:
frosja888 [35]2 years ago
3 0
1.7 s<span>, then the </span>velocity<span> of the </span>baseball<span> is 22.35 </span>m/s<span> toward first base. hope this helps.</span>
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A tree with a height of 12 yards casts a shadow that is 33 yards long at a certain time of day. At the same time, another tree n
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4 0
2 years ago
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A jar contains 27 marbles. There are 4 blue marbles and the rest are red. If a marble is chosen at random, what is the likelihoo
ikadub [295]

Answer:

23/27

Step-by-step explanation:

27-4=23

8 0
2 years ago
Kelly blends coffee. She mixes brand A costing $6 per kilogram with brand B costing $8 per kilogram. How many kilograms of each
sukhopar [10]

Step-by-step explanation:

Let

x

be the kg of coffee of brand A in the mix and

y

be the kg of coffee of brand B in the mix.

The total kg must be

50

.

x

+

y

=

50

The cost per kg of the mix must br

$

7.20

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6

x

+

8

y

, so the total cost per kg of the mix will be

6

x

+

8

y

50

.

6

x

+

8

y

50

=

7.20

Now that we have our two equations, we can solve.

6

x

+

8

y

=

7.20

⋅

50

6

x

+

8

y

=

360

From the first equation, we can multiply both sides by

6

to get:

6

x

+

6

y

=

300

Subtracting, we get:

2

y

=

60

y

=

30

Thus, we need

30

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6 0
1 year ago
Which congruence theorems can be used to prove ΔEFG ≅ ΔJHG? Select two options.
mezya [45]
<h2><u><em>Answer: </em></u></h2><h2><u><em> </em></u></h2>

ASA  and AAS

<h2><u><em>Step-by-step explanation: </em></u></h2>

We do not know if these are right triangles; therefore we cannot use HL to prove congruence.

We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.

We are given that EF is parallel to HJ.  This makes EJ a transversal.  This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent.  We also know that ∠EGF and ∠HGJ are vertical angles and are congruent.  This gives us two angles and a non-included side, which is the AAS congruence theorem.

Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent.  Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.

5 0
2 years ago
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babymother [125]
6$ cost of the catalog
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2 years ago
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