Question

At a recent audition school play, 1 out of 3 students who auditioned were asked to come to a second audition . After the second audition ,75% of those asked to the second audition were offered parts. If 18 students were offered parts , how many students were offered to the first audition

Answer 1

Answer:

The total students appearing in first audition = 72

Step-by-step explanation:

As given in the question:

1 out of 3 students were asked to come for second audition.

Let us assume the TOTAL STUDENT who came to first audition =  m

So, $(\frac{1}{3}) m$ appeared for the SECOND ROUND.

Now, 75% of students appearing in second audition were offered parts.

Calculating 75% of  $(\frac{1}{3}) m$

$\frac{75}{100} \times\frac{1}{3} m = 0.25 m$

Also, as said 18 students were offered parts.

⇒ 0. 25 m = 18

Now, solving for m, we get:

m = 18/0.25  = 72

or, m = 72

Hence, the total students appearing in first audition = 72