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Ksivusya [100]
2 years ago
13

762,508 expanded form using exponents

Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
6 0

762,508 in expanded form using exponents is given as:

7 \times 10^5 + 6 \times 10^4 + 2 \times 10^3 + 5 \times 10^2 +0 \times 10^1 + 8 \times 10^0

<h3><u>Solution:</u></h3>

Given that we have to write 762, 508 in expanded form using exponents

Expanded form or expanded notation is a way of writing numbers to see the math value of individual digits

<h3><u>Write 762508 in Expanded form</u></h3>

Let us first find the place value of digits

Place value can be defined as the value represented by a digit in a number on the basis of its position in the number.

Place value of 7 = 700000

In 762508, 7 is in hundred-thousands place

Place value of 6 = 60000

In 762508, 6 is in ten-thousands place.

Place value of 2 = 2000

In 762508, 2 is in thousands place

Place value of 5 = 500

In 762508, 5 is in hundreds place

Place value of 0 = 0 x 10 = 0

In 762508, 0 is in tens place

Place value of 8 = 8

In 762508, 8 is in ones place

Therefore, the expanded form is given as:

700,000 + 60,000 + 2,000 + 500 + 0 + 8

<u><em>Using exponents we can write as,</em></u>

7 \times 10^5 + 6 \times 10^4 + 2 \times 10^3 + 5 \times 10^2 +0 \times 10^1 + 8 \times 10^0

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

P(\bar X

P(\bar X

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent interest on this case, and for this case we know the distribution for X is given by:

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Solution to the problem

We want this probability:

P(\bar X

The best way to solve this problem is using the normal standard distribution and the z score given by:

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If we apply this formula to our probability we got this:

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