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2 years ago

1) A group of five friends goes to the state fair. Each friend pays the entrance fee and buys

Mathematics

1 answer:

kari74 [83]2 years ago

8 0

Answer:

$5(d - 4)$

Step-by-step explanation:

Entrance fee per head = d

Entrance fee for the 5 friends = 5*d = 5d

Booklet of ride ticket per head = 2.5d

Booklet of ride ticket for the 5 friends = 5(2.5d)

Meal ticket per head = d - 4

Meal ticket for the 5 friends = 5(d - 4)

Total amount paid altogether by the five friends = $5d + 5(2.5d) + 5(d - 4)$

From this breakdown above, the total amount paid by the 5 friends for their meal tickets = $5(d - 4)$

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Janice works at a cell phone company. She wants to make a presentation to her team about the features of a new phone. She makes

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If 1 inch represents 0.5 centimeter, then 28 inches will represent 28 * 0.5 = 14 centimeters and 15 inches will represent 15 * 0.5 = 7.5 centimeters.

The actual dimensions of the phone is: the length is 14 centimeters and the width is 7.5 centimeters.

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2 years ago

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Solve 3x + 2 = 15 for x using the change of base formula log base b of y equals log y over log b. −1.594 0.465 2.406 4.465

disa [49]

<u>Answer:</u>

The value in 3x + 2 = 15 for x using the change of base formula is 0.465 approximately and second option is correct one.

<u>Solution:</u>

Given, expression is $3^{(x+2)}=15$

We have to solve the above expression using change of base formula which is given as

$\log _{b} a=\frac{\log a}{\log b}$

Now, let us first apply logarithm for the given expression.

Then given expression turns into as, $x+2=\log _{3} 15$

By using change of base formula,

$x+2=\frac{\log _{10} 15}{\log _{10} 3}$

x + 2 = 2.4649

x = 2.4649 – 2 = 0.4649

Hence, the value of x is 0.465 approximately and second option is correct one.

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2 years ago

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Sheldon is creating a graph to represent the trip he takes from his home to his favorite clothing store. In his graph, one unit

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Answer:

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Step-by-step explanation:

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2 years ago

Name two ways you might see decimals used outside of school.

slega [8]

In money and weighing things

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2 years ago

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Suppose that 4% of the 2 million high school students who take the SAT each year receive special accommodations because of docum

dangina [55]

Answer:

a. 0.0122

b. 0.294

c. 0.2818

d. 30.671%

e. 2.01 hours

Step-by-step explanation:

Given

Let X represents the number of students that receive special accommodation

P(X) = 4%

P(X) = 0.04

Let S = Sample Size = 30

Let Y be a selected numbers of Sample Size

Y ≈ Bin (30,0.04)

a. The probability that 1 candidate received special accommodation

P(Y = 1) = (30,1)

= (0.04)¹ * (1 - 0.04)^(30 - 1)

= 0.04 * 0.96^29

= 0.012244068467946074580191760542164986632531806368667873050624

P(Y=1) = 0.0122 --- Approximated

b. The probability that at least 1 received a special accommodation is given by:

This means P(Y≥1)

But P(Y=0) + P(Y≥1) = 1

P(Y≥1) = 1 - P(Y=0)

Calculating P(Y=0)

P(Y=0) = (0.04)° * (1 - 0.04)^(30 - 0)

= 1 * 0.96^36

= 0.293857643230705789924602253011959679180763352848028953214976

= 0.294 --- Approximated

The probability that at least 2 received a special accommodation is given by:

P (Y≥2) = 1 -P(Y=0) - P(Y=1)

= 0.294 - 0.0122

= 0.2818

d. The probability that the number among the 15 who received a special accommodation is within 2 standard deviations of the number you would expect to be accommodated?

First, we calculate the standard deviation

SD = √npq

n = 15

p = 0.04

q = 1 - 0.04 = 0.96

SD = √(15 * 0.04 * 0.96)

SD = 0.758946638440411

SD = 0.759

Mean =np = 15 * 0.04 = 0.6

The interval that is two standard deviations away from .6 is [0, 2.55] which means that we want the probability that either 0, 1 , or 2 students among the 20 students received a special accommodation.

P(Y≤2)

P(0) + P(1) + P(2)

P(0) + P(1) = 0.0122 + 0.294

Calculating P(2)

P(2) = (0.04)² * (1 - 0.04)^(30 - 2(

P(2) = 0.00051

So,

P(0) +P(1) + P(2). = 0.0122 + 0.294 + 0.00051

= 0.30671

Thus it 30.671% probable that 0, 1, or 2 students received accommodation.

The expected value from d) is .6

The average time is [.6(4.5) + 19.2(3)]/30 = 2.01 hours

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2 years ago