Alright, lets get started.
If Matthew wants to complete packages at an average rate of at least 39 packages per hour.
And they worked 4 hrs only due to picnic, yesterday, it means they have to make
packages.
But they made only 112 packages means they are short of
packages.
Suppose they are working today t hrs, and his department will complete 43 packages per hour today.
It means they are going to make 43 t packages today.
This 43 t packages includes those 44 too , which they are short of yesterday due to picnic.
So, average will be
(39 average given in question)
Cross multiplying

Adding 44 in both sides


Subtracting 39 t in both sides


Dividing 4 in both sides
t = 11 hrs
Hence they have to woth 11 hrs today : Answer
Hope it will help :)
Answer:
The first pizza is 6 slices, so each slice is 1/6 of a pizza. The second pizza is 4 slices, so each slice is 1/4 of a pizza. If you were to take one slice of each, you would get 1/6 +1/4 slice, which would be 5/12 of a pizza, as opposed to if you took 2 slices of the first pizza, which would only be 4/12 of a pizza.
Answer:
The perimeter of Δ ABC is 20 + 2
units ⇒ Last answer
Step-by-step explanation:
The perimeter of any triangle is the sum of the lengths of its three sides
The formula of distance between two points is
In Δ ABC
∵ A = (3 , 4) , B = (-5 , -2) , C = (5 , -2)
∵ AB = 10 units
∵ AC = 2
- To find its perimeter find the length of BC
∵
= -5 and
= -2
∵
= 5 and
= -2
- By using the formula above
∴ 
∴ 
∴ BC = 10 units
To find the perimeter add the lengths of the three sides
∵ P = AB + BC + AC
∴ P = 10 + 10 + 2
- Add like terms
∴ P = 20 + 2
The perimeter of Δ ABC is 20 + 2
units
Answer: D) 
Step-by-step explanation:
As per given , we have
Sample size : n= 15
sample mean : 
Sample standard deviation: s= $20
Since population standard deviation is unknown , so we use t-test.
Significance level for 95% confidence : 
Critical t-value :
[Using students' t-value table]
Required 95% Confidence interval :-

Hence, the required 95% confidence interval for the mean amount its credit card customers spent on their first visit to the chain's new store in the mall assuming that the amount spent follows a normal distribution.:
