Answer:We can see that this is dependent probability. We can find dependent probability of happening event A then event B by multiplying probability of event A by probability of event B given that event A already happened.
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Step-by-step explanation:In our case event A is pirate hitting captain's ship and event B is captain missing pirate's ship.
We have been given that pirate shoots first so pirate's ship can't be hit before pirate shoots his cannons. So probability of hitting captain's ship is 1/3.
We have been given that if Captain Ben's ship is already hit then Captain Ben will always miss. So the probability of Captain missing the dread pirate's ship given the pirate Luis hitting the Captain ship is 1.
Now to find probability that pirate hits Captain, but Captain misses we will multiply our both probabilities.
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Answer: The correct option is first, the number of basketball hoops did the company previously produce to make the same profit is 1.3 million hoops.
Explanation:
Let the number of basketball hoops did the company previously produce to make the same profit be x.
Total Revenue = Price * Quantity
The total revenue in million dollars is,


The total cost in million dollars is,
Total Cost = One unit cost * Quantity

Profit = Total Revenue - Total Cost

The profit is 15 million.


The value of x is 1 and
.
The production is always positive therefore the value of x either 1 or 1.3. Since 1 million is not available in the options therefore the the correct optin is 1.3 million hoops.
Given:
6kg 650g
1/2 kg
1/2 kg is equal to 500 grams
1 kg = 1000 grams
We need to convert these figures from kg to g.
6 kg * 1000g/kg = 6*1000g = 6,000 g
6,000 g + 650 g = 6,650 g
6,650 g ÷ 500 g = 13.3 round off to 13
13 * 500 g = 6,500
6 kg 650 g is nearest to 6,500 g.
Answer:
$163.54
Step-by-step explanation:
Volume of rectangular container = 10m^3
Length = 2(width)
Material for the base cost $10 per square meter
Material for the side cost $6 per square meter
Volume = L*B*H
L= 2W
V = (2W).W. H
10 = 2W^2.H
H = 10 /2W^2
H = 5/W^2
Let C(w) = cost function
C(w) = 10(L.W) + 6(2.L.H + 2.W.H)
= 10(2W.W) + 6(2.2W.H + 2.W.H)
= 10(2W^2) + 6(4W.H + 2.W.H)
= 10(2W^2) + 6(4W*5/W^2 + 2.W*5/W^2)
= 20W^2 + 6(20/W + 10/W)
= 20W^2 + 6((10+20)/W)
= 20W^2 + 6(30/W)
C(w) = 20W^2 + 180/W
To find the minimum value, differentiate C with respect to w
C'(w) = 40W - 180/W^2
Put C'(w) = 0
0 = 40W - 180/W^2
40W = 180/W^2
40W^3 = 180
W^3 = 180/40
W^3 = 4.5
W = cube rt(4.5)
W = 1.65m
C = 20(1.65)^2 + 180/1.65
C = 54.45 + 109.09
C= $163.54
Minimum cost = $163.54
First we find the area 10 x 21 = 210 then we multiply 210 x .70 and we get 147.00 total cost. d. 147.00