Answer:
The answer is b ($9.74)
Step-by-step explanation:
I got it right (:
Notice that

so the constraint is a set of two lines,

and only the first line passes through the first quadrant.
The distance between any point
in the plane is
, but we know that
and
share the same critical points, so we need only worry about minimizing
. The Lagrangian for this problem is then

with partial derivatives (set equal to 0)



We have

which tells us that

so that
is a critical point. The Hessian for the target function
is

which is positive definite for all
, so the critical point is the site of a minimum. The minimum distance itself (which we don't seem to care about for this problem, but we might as well state it) is
.
Answer: 250 mi
Step-by-step explanation:
Here we can think in a triangle rectangle:
The distance from Birmingham to Atlanta is roughly 150 mi, and this is one of the cathetus.
And the distance from Birmingham to Nashville is roughly 200 mi, this is the other cathetus of the triangle.
Now, the distance from Atlanta to Nashville will be the hypotenuse of this triangle rectangle.
Now we can apply the Pythagorean's theorem:
A^2 + B^2 = H^2
Where A and B are the cathetus, and H is the hypotenuse:
Then:
H = √(A^2 + B^2)
H = √(150^2 + 200^2) mi = √(62,500) mi = 250 mi
Then the estimated distance from Atlanta to Nashville is 250 mi
Answer:
B
Step-by-step explanation:
The order does not matter. The intersection point will be the same regardless of the order the arcs are drawn in.
The correct answer for the question that is being presented above is this one: "The axis of symmetry is to the left of zero." The a value of a function in the form f(x) = ax2 + bx + c is negative. The statement must be true is this The axis of symmetry is to the left of zero.<span>
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