Answer:
The major condition that needs to be satisfied before a t-test is performed that the question satisfies easily is the use of random sampling to obtain sample data.
Step-by-step explanation:
The major conditions necessary to conduct a t-test about a mean include;
- The sample extracted from the population must be extracted using random sampling. That is, the sample must be a random sample of the population.
- The sampling distribution must be normal or approximately normal. This is achievable when the population distribution is normal or approximately normal.
- Each observation in the sample data must have an independent outcome. That is, the outcome/result of each sub-data mustn't depend on one another.
Of the three conditions that need to be satisfied before the conduction of a t-test, the first condition about using a random sampling technique is evidently satisfied.
It is stated in the question that 'A private investigator hired by a competitor takes a random sample of 47 games and tries to determine if there are more than 7 glitches per game'.
Hope this Helps!!!
Answer:
$0.85
Step-by-step explanation:
2 juice pouches- $2.50
3c+2.50=5.05 (c is for bags of chips)
3c=5.05-2.50
3c=2.55
c= $0.85
So one bag of chip is $0.85
Answer:
Zscore = 0.5
Step-by-step explanation:
If we assume a normal distribution, we mean that the diameters of each tomato follow a normal distribution. This is N~ (0,1).
By that, we mean that the mean (μ) = 0 and variance (
) = 1. Thus, since we are told that one tomato was in the 50th percentile. This implies the median. And is 0.5. And if the distribution is normal, the mean and median and mode should be equal.
Thus:
==> Z score = 
= 
Answer:
$26.06
Step-by-step explanation:
You would like to purchase a glue gun for $8.99 and a basket for $25.99. The highest-priced item is a basket for $25.99. So, the coupon will take the discount off for this item.
The new price of the basket is
The total cost of your buying is
There will be a 6% sales tax added to the price of all items. So, the end cost is
Answer: b. 0.8413
Step-by-step explanation:
Given : The average time taken to complete an exam, X, follows a normal probability distribution with 
and 
.
Then, the probability that a randomly chosen student will take more than 30 minutes to complete the exam will be :-
![P(x>30)=P(z>\dfrac{30-60}{30})\ \ [\because\ z=\dfrac{x-\mu}{\sigma} ]\\\\=P(z>-1)=P(z-z)=P(Z](https://tex.z-dn.net/?f=P%28x%3E30%29%3DP%28z%3E%5Cdfrac%7B30-60%7D%7B30%7D%29%5C%20%5C%20%5B%5Cbecause%5C%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%20%5D%5C%5C%5C%5C%3DP%28z%3E-1%29%3DP%28z%3C1%29%5C%20%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3E-z%29%3DP%28Z%3Cz%29%5D%5C%5C%5C%5C%3D%200.8413)
[using z-value table]
Hence, the probability that a randomly chosen student will take more than 30 minutes to complete the exam = 0.8413
