Answer:
A. Salamanders
Explanation:
Specialists species are species that can thrive in a unique and limited range of resources. They require a specific environmental condition to reproduce and survive in environment and also have limited or few diets they need for nutrition. These limiting characteristics put them at a disadvantage of being endangered and threatened.
Salamanders are endangered species that are fast going into extinction. They require wetland (freshwater pools) for reproduction to be possible, and feed mainly on insects. This makes them specialist species.
Ospreys, snapping turtles, and beavers are all generalist species. They can all thrive in a wide range of environmental conditions, and also have varieties of diets they can get nutrition from to survive.
<h2>The Forearm</h2>
Explanation:
The proximal end of the radius illustrates the relationship of form and function. The cup-like surface of the radial head articulates with the rounded shape of the capitulum. This forms a joint that allows for movement of elbows and forearms.
Radius and ulna are the two bones of the forearm. Their proximal ends articulate and fit into the cup like end of the humerus. This forms a synovial joint called the elbow joint. The movement of this joint allows the forearms to supinate and pronate.
<span>The answer is A.
Invasive species are species that thrive unregulated
in an introduced environment/ habitat and
affect the biodiversity of the environment.
They boom unchecked mostly due to lack of a natural predator. Therefore, introducing
a predator will limit their growth. </span>
Answer:
Two
Recessive
Loss
Explanation:
To cause cancer, tumor suppressor genes require two alleles to be mutated and therefore are considered recessive. The mutation results in a loss of function.
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
