Answer:
Superficial part: maxillary process of zygomatic bone, Inferior border of zygomatic arch (anterior 2/3)
Deep part: deep/inferior surface of zygomatic arch (posterior 1/3)
Explanation:
Answer:
See the answer below
Explanation:
Let the disorder be represented by the allele a.
Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.
Since the four adults are carriers, their genotypes would be Aa.
Aa x Aa
Progeny: AA 2Aa aa
Probability of being affected = 1/4
Probability of being a carrier = 1/2
Probability of not being affected = 3/4
(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2
(b) The chance that the third child of Sara and James will be free of the condition = 3/4
(c)
(d) If someone has no family history of the disorder, their genotype would be AA.
AA x aa
4 Aa
<em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history </em>= 0
(e)
(f) <em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history</em> = 0
I assume that in this item, we are asked to solve for the force exerted during the heartbeat. Force is the product of the mass and acceleration. To solve for the acceleration in this item, we divide the velocity by time.
a = 1 m/s / 0.2 s = 5 m/s²
Then, we multiply this by the mass (in kg)
F = (80 g / 1000 g/kg) x (5 m/s²)
= 0.4 kg m/s² = 0.4 J
Therefore, every hearbeat will take 0.4 J of force.
Reactants of photosynthesis include light energy, H2O, and CO2. So I would imagine it’s H2O and CO2
