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KiRa [710]
2 years ago
15

A company has two large computers. The slower computer can send all the company's email in 60 minutes. The faster computer can c

omplete the same job in 40 minutes. If both computers are working together, how long will it take them to do the job? Do not do any rounding.
Mathematics
1 answer:
Lelu [443]2 years ago
4 0

Answer:

If both computers are working together, it will take 24 minutes to do the job

Step-by-step explanation:

It is given that,

There are two computers.The slower computer can send all the company's email in 60 minutes.

The faster computer can complete the same job in 40 minutes

<u>To find the LCM of 40 and 60</u>

LCM (40, 60) = 120

<u>To find efficiency of 2 computers</u>

Let x be the efficiency of faster computer and y be the efficiency of faster computer

x = 120/40 = 3

y = 120/60 = 2

then, x + y = 3 + 2 = 5

Therefore efficiency of both the computer work together = x + y =5

<u>To find the time taken to work both the computer together</u>

time = 120/5 = 24 minutes

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\bf n^{th}\textit{ term of an arithmetic sequence}\\\\&#10;a_n=a_1+(n-1)d\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;d=\textit{common difference}\\&#10;----------\\&#10;n=7\\&#10;d=5\\&#10;a_7=34&#10;\end{cases}&#10;\\\\\\&#10;a_7=a_1+(7-1)5\implies 34=a_1+(7-1)5&#10;\\\\\\&#10;34=a_1+30\implies \boxed{4=a_1}

and now let's use those 2 found folks, to get the 21st term,

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\&#10;a_n=a_1+(n-1)d\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;d=\textit{common difference}\\&#10;----------\\&#10;a_1=4\\&#10;d=5\\&#10;n=21&#10;\end{cases}&#10;\\\\\\&#10;a_{21}=4+(21-1)5\implies a_{21}=4+100\implies a_{21}=104
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