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2 years ago

For every 20 litres of petrol a car can run for 75 km.

Mathematics

1 answer:

densk [106]2 years ago

3 0

Answer:

<u>52.3 litres</u>.

Step-by-step explanation:

The car consumption is 75/20 = 3.75 km/litre.

Volume of petrol needed to travel 196 km

= 196 / 3.75 = 52.3 litres.

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1) Consider the sequence:

Ivan

Answer:

1) The 38th term is A. 38

2) The 11th term is D. 3072

3) The 3rd term is C. 34

Step-by-step explanation:

1) I added 2 until I got to the 38th term.

2) I multiplied until I got to the 11th term.

3) I added 3 until i got to the 12th term.

The teacher showed a more complex way to do it but this is just what I did.

I took the quiz, so I know that I got them all correct.

5 0

2 years ago

Read 2 more answers

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Tanzania [10]

Answer:

Approximately, 159 men weighs more than 165 pounds and 159 men weighs less than 135 pounds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 150 pounds

Standard Deviation, σ = 15

We are given that the distribution of weights of 1000 men is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P( men weighing more than 165 pounds)

P(x > 165)

$P( x > 165) = P( z > \displaystyle\frac{165 - 150}{15}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 165) = 1 - 0.8413 = 0.1587 = 15.87\%$

Approximately, 159 men weighs more than 165 pounds.

P(men weighing less than 135 pounds)

P(x < 135)

$P( x < 135) = P( z < \displaystyle\frac{135 - 150}{15}) = P(z < -1)$

Calculation the value from standard normal z table, we have,

$P(x < 135) = 0.1587 = 15.87\%$

Approximately, 159 men weighs less than 135 pounds.

6 0

2 years ago

Agent Hunt is transferring classified files from the CIA mainframe to his flash drive. The variable S models the size of the fil

amid [387]

Answer:

Step-by-step explanation:

$\bold{METHOD\ 1:}\\\\\text{Calculate the value of }S\ \text{in}\ 10s,\ 20s,\ 30s,\ ... \text{and difference if them}\\\\for\ t=10:\\\\S=5(10)+45=50+45=95\\\\for\ t=20:\\\\S=5(20)+45=100+45=145\\\\for\ t=30:\\\\S=5(30)+45=150+45=195\\\\195-145=50\\145-95=50\\\\\boxed{50\ MB\ per\ 10s}$

$\bold{METHOD\ 2:}\\\\S_1=5t+45\to \text{in t second}\\\\S_2=5(t+10)+45\to \text{10 second leter}\\\\\text{Difference}\\\\S_2-S_1=5(t+10)+45-(5t+45)=5t+50+45-5t-45=50\\\\\boxed{50MB\ per\ 10s}$