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garik1379 [7]
1 year ago
12

What does Mark Twain satirize in this excerpt from "The £1,000,000 Bank-Note"? It was a lovely dinner-party of fourteen. The Duk

e and Duchess of Shoreditch, and their daughter the Lady Anne-Grace-Eleanor-Celeste-and-so-forth-and-so-forth-de-Bohun, the Earl and Countess of Newgate, Viscount Cheapside, Lord and Lady Blatherskite, some untitled people of both sexes, the minister and his wife and daughter, and his daughter's visiting friend, an English girl of twenty-two, named Portia Langham, whom I fell in love with in two minutes, and she with me—I could see it without glasses. There was still another guest, an American—but I am a little ahead of my story. A. the long list of names required to address certain nobles B. the English customs of hosting frequent dinner parties C. the lack of importance given to Americans by Englishmen D. the eccentric and absurd practices of the British upper class
English
2 answers:
koban [17]1 year ago
8 0

Answer:

the long list of names required to address certain nobles

Explanation:

dalvyx [7]1 year ago
4 0

Hope it Helps :)


I believe Mark Twain is satirizing 'the long list of names required to address certain nobles' in this excerpt. Because, there is no mention of balls and dinner parties, or the importance of the Americans/British, or their eccentric attitudes, therefore, the first option is the correct one.



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Answer:

Weight of silver coin = 29.25 units , weight of gold coin = 35.75 units

Explanation:

Let the weight of 1 gold coin be W_{1}

Weight of 1 silver coin be W_{2}

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9W_{1}=11W_{2}............(i)

After replacing coins the weights become as under

Gold Stack\\9W_{1}-W_{1}+W_{2}=8W_{1}+W_{2}\\\\SilverStack\\\\11W_{2}-W_{2}+W_{1}=10W_{2}+W_{1}

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the above relation modifies as

8W_{1}+W_{2}+13=10W_{2}+W_{1}\\7W_{1}+13=9W_{2}..........(ii)

8W_{1}+W_{2}+13=10W_{2}+W_{1}\\7W_{1}+13=9W_{2}..........(ii)\\\\7\frac{11W_{2}}\\\\Solving equation i and ii we get\\\\{9}+13=9W_{2}\\\\77W_{2}+117=81W_{2}\\\\4W_{2}=117\\\\W_{2}=\frac{117}{4}=29.25units\\\\W_{1}=\frac{11W_{2}}{9}=35.75units

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