These are the correct answers to the following questions:
<span>1. Barney and Betty are about to have their first child. They both have "normal" feet but Barney's father has flat feet and Betty has a child from a previous marriage who has flat feet, meaning they are both heterozygous for the trait. What is the probability that they will have a boy with flat feet(recessive trait)?
A.25%
B.50%
C.100%
D.75%
2. humans, the ability to roll the tongue is a dominant trait. The inability to roll the tongue is a recessive trait. If two individuals homozygous recessive for this trait have a child, what is the chance that the child will be able to roll his tongue?
A.100%
B.0%
C.50%
D.25%</span>
<span>Hippocrates believed that there are four humors in human body which need balance for a healthy being. These were:
Blood, phlegm, yellow bile, and black bile.</span>
Galen expanded the idea of the humors and introduced four temperaments which were these:
choleric (hot / dry), melancholic (cold / dry), sanguine (warm / moist), and phlegmatic (cold / moist).
Another expansion Galen did was that he gave each humor/temperament physical and psychological qualities and said that even the food items have an association with the certain humor, those foods can effect certain humor in certain ways.
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
