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BartSMP [9]
2 years ago
11

A small-appliance manufacturer finds that the profit P (in dollars) generated by producing x microwave ovens per week is given b

y the formula P = 1 /10 x (300 − x) provided that 0 ≤ x ≤ 200. How many ovens must be manufactured in a given week to generate a profit of $1610?
Mathematics
1 answer:
Olegator [25]2 years ago
7 0

Answer:

Number of ovens must be manufactured in a given week to generate a profit of $1610  is 70

Step-by-step explanation:

We are given

A small-appliance manufacturer finds that the profit P (in dollars) generated by producing x microwave ovens per week is given by the formula

P=\frac{1}{10}x(300-x)

provided that 0 ≤ x ≤ 200

We are given

profit is $1610

so, we can set P=1610

and then we can solve for x

1610=\frac{1}{10}x(300-x)

Multiply both sides by 10

1610\cdot \:10=\frac{1}{10}x\left(300-x\right)\cdot \:10

16100=x\left(300-x\right)

16100=300x-x^2

-x^2+300x-16100=0

now, we can factor it

(x-70)(x-230)=0

we can solve for x

and we get

x=70,x=230

Since, x=230 does not lie on 0 ≤ x ≤ 200

So, we will consider only x=70

So,

Number of ovens must be manufactured in a given week to generate a profit of $1610  is 70


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Seventy cards are numbered 1 through 70, one number per card. One card is randomly selected from the deck. What is the probabili
miskamm [114]

Given:

Seventy cards are numbered 1 through 70, one number per card. One card is randomly selected from the deck.

To find:

The probability that the number drawn is a multiple of 3 and a multiple of 5.

Solution:

Total number from 1 to 70 = 70

Multiple of 3 from 1 to 70 are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69.

Multiple of 5 from 1 to 70 are 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70.

Numbers which are multiply of both number 3 and 5 = 15, 30, 45, 60

Number of favorable outcomes = 4

Probability=\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}

Probability=\dfrac{4}{70}

Probability=\dfrac{2}{35}

Therefore, the required probability is \dfrac{2}{35}.

7 0
2 years ago
Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The
abruzzese [7]

The question is incorrect.

The correct question is:

Three TAs are grading a final exam.

There are a total of 60 exams to grade.

(c) Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The TAs grade at different rates, so the first TA will grade 25 exams, the second TA will grade 20 exams and the third TA will grade 15 exams. How many ways are there to distribute the exams?

Answer: 60!/(25!20!15!)

Step-by-step explanation:

The number of ways of arranging n unlike objects in a line is n! that is ‘n factorial’

n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1

The number of ways of arranging n objects where p of one type are alike, q of a second type are alike, r of a third type are alike is given as:

n!/p! q! r!

Therefore,

The answer is 60!/25!20!15!

6 0
2 years ago
Paul makes a base monthly salary of $1500.As a vendor,he must sell %19000 worth of items per month.He also makes a 6% commission
Orlov [11]

Answer:

$3000

Step-by-step explanation:

3 0
2 years ago
A mouse traveled a total distance of 3/24 of a mile in a maze over the past three hours the mouse travel the same distance each
alexgriva [62]

Answer:

Total distance mouse traveled in 3 hours = \frac{3}{24} of a mile

The mouse traveled the same distance in each hour. So in order to find the distance covered in 1 hour we have to divide the distance covered in 3 hours by 3. This will give us the distance that the mouse traveled in one hour.

So, the distance traveled in one hour will be = \frac{3}{24} \div 3 = \frac{3}{24} \times \frac{1}{3} =\frac{1}{24} of a mile

The error which Matt made was that he divided only the denominator of the expression by 3, this probably was a calculation error.

Correct conclusion will be: Mouse travel 1/24 of a mile each hour

8 0
2 years ago
Box A is 567 inches high, 678 inches wide, and 789 inches long. It has a maximum capacity of 1,200 marbles, Box B has three time
kotykmax [81]

Answer:

1701 high

2712 wide

789 long

= 4413

Step-by-step explanation:

3 0
2 years ago
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