Answer:
#include <stdlib.h>
#include <time.h>
#include<iostream.h>
int main(void) {
int seedVal = 0;
seedVal = 4;
srand(seedVal);
/* Solution*/
cout<<rand() % 149 + 100<<endl;
cout<<rand() % 149 + 100<<endl;
return 0;
}
Explanation:
We start with the required include statements to enable use of srand, rand and time functions. I have also added iostream library to use "cout" function.
After that, the seed is initialized using srand(). And then the two rand functions are called with ranges including and between 100 and 149, and printed out.
Solution:
In the game Singularity, broken objects can be restored to their original condition by reversing time. This is an example of which time element of player adjustment.
Thus the required answer is player adjusted.
Answer:
The answer is "Option 2".
Explanation:
- All the other drivers replicate even existing technical embedded devices. These systems have optimistic, and they are commonly accessible to inbox operators as most web browsers. It is an Imitated device, that performance problems because of all the emulator is the workload.
- Integration Services is a program package, which is created on a guest OS of a VM, that provides enhanced guest OS drivers and improves accuracy, functionality for IDE and SCSI storage systems, networking interfaces, and monitor and multimedia devices, that's why it is incorrect.
<u>Answer:</u>
<em>1. The loop will run unless the value of answer equals to Capital N.</em> The method equals is “case-sensitive” that is lower case letter and upper case letters are considered different. That “a” and “A” means the same to us, but for the method equals it is different and equals method will return false if the case is not matching.
<em>2. a (int)(Math.random() * (upper − lower) ) + lower </em>
Since we need to consider the lower limit value together to get the desired results we need to add the value of lower limit to the multiplied answer.
<em>3. b while(userGuess != secretNumber || userGuess >= lowerLimit && userGuess <= upperLimit)</em>
Here the program is required to check the while loop and exit when user guess the number or we can say the loop should continue until the user guess the number, so that is why we have taken <em>userGuess!=secretNumber. </em>Next the loop should be exited if it is not within the range or we can say that the loop should run only if the guessed number is within the upper and lower limit.<em> That is why we have opted for the condition userGues>=lowerlimit && userGuess<=upperlimit.</em> Why we have taken && as the operator is that, it’s a range of values so && operator best suit for this kind of logical condition.
Answer:
The output is:
R
M
N
Explanation:
The code snippet print the beginning letter of each word in the given name.
In the for loop snippet:
first the program check if startWord is true and it is true, then it print the value of the character at index 0. Then it check if value of character is empty. If it is empty, startWord is initialized to true else it is initialized to false.
The loop only print a character when the value of i are 0, 8 and 11 which are also the beginning character of a word.
