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Use an inequality symbol (<, >, =, ≥) to compare −17 ____ −1

iragen [17]

-17 is less than -1 so you will use the less than sign (<)

Answer: 17 __<__-1

< is less than
> is greater than
= is equal to
<span>≥ is greater than or equal to</span>

3 0

2 years ago

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The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillat

Greeley [361]

Answer:

1) $L \propto T^2$

Using the condition given:

$2.205 m = K (3)^2$

$K = 0.245 \approx \frac{g}{4\pi^2}$

So then if we want to create an equation we need to do this:

$L = K T^2$

With K a constant. For this case the period of a pendulumn is given by this general expression:

$T = 2\pi \sqrt{\frac{L}{g}}$

Where L is the length in m and g the gravity $g = 9.8 \frac{m}{s^2}$ .

2) $T = 2\pi \sqrt{\frac{L}{g}}$

If we square both sides of the equation we got:

$T^2 = 4 \pi^2 \frac{L}{g}$

And solving for L we got:

$L = \frac{g T^2}{4 \pi^2}$

Replacing we got:

$L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m$

3) $T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s$

Step-by-step explanation:

Part 1

For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.

$L \propto T^2$

Using the condition given:

$2.205 m = K (3)^2$

$K = 0.245 \approx \frac{g}{4\pi^2}$

So then if we want to create an equation we need to do this:

$L = K T^2$

With K a constant. For this case the period of a pendulumn is given by this general expression:

$T = 2\pi \sqrt{\frac{L}{g}}$

Where L is the length in m and g the gravity $g = 9.8 \frac{m}{s^2}$ .

Part 2

For this case using the function in part a we got:

$T = 2\pi \sqrt{\frac{L}{g}}$

If we square both sides of the equation we got:

$T^2 = 4 \pi^2 \frac{L}{g}$

And solving for L we got:

$L = \frac{g T^2}{4 \pi^2}$

Replacing we got:

$L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m$

Part 3

For this case using the function in part a we got:

$T = 2\pi \sqrt{\frac{L}{g}}$

Replacing we got:

$T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s$

8 0

2 years ago

A firm advertises for workers to address envelopes. Priscilla says she will work 100 hours. Herb will work for 80 hours. If each

charle [14.2K]

Combined work problems
job/time + job/time = job/ total time

(1/80) + (1/100) = 1/T
(10/800) + (8/800) = 1/T
18/800 = 1/T
800/18 = T
44.44 hrs = T

4 0

2 years ago

4.5x-7=20 i need help whats the answer

Dmitry [639]

Your answer will be 6.

7 0

2 years ago

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Mr. Lobo is building a fence rectangular around his rectangular yard. It is 16 feet long and 14 feet wide. How much feet of feet

lawyer [7]

Answer:

30

Step-by-step explanation:

14+16 1. Break it down 14 is equal to 10+4 16 is equal to 10+6 2. Add the biggest numbers together first 10+10 = 20 3. Add the smaller numbers together 6+4 = 10 4. Add all of the numbers together 20+10 = 30

4 0

2 years ago