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Simora [160]
2 years ago
9

Last year the girls’ basketball team had 8 fifth-grade students and 7 sixth-grade students. What was the ratio of sixth-grade st

udents to fifth-grade students on the team?
Mathematics
2 answers:
attashe74 [19]2 years ago
6 0

7:8 it could also be written as 7 to 8 or 7/8

Since we need to find out SIXTH to FIFTH grades we have to put the sixth graders first. Hope this helps and have a great day!

timofeeve [1]2 years ago
4 0

Answer:

the ratio of the sixth-grade students to fifth-grade students on the team is 7 : 8

Step-by-step explanation:

Given Parameters

Fifth grade students of the basket team = 8

Sixth grade students of the basket team = 7

Required;

Ratio of the sixth-grade students to fifth-grade students on the team

Let F represent the fifth graders

F = 8

Let S represent the sixth graders

S = 7

The ratio of S to F is represented mathematically by S : F

By substituton

S : F becomes

7 : 8

Hence, the ratio of the sixth-grade students to fifth-grade students on the team is 7 : 8

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Assuming a binomial distribution, a production process produces 2% defective parts. A sample of five parts from the production p
Murrr4er [49]

Answer:

0.38% probability that the sample contains exactly two defective parts.

Step-by-step explanation:

For each part, there are only two possible outcomes. Either it is defective, or it is not. The probabilities for each part being defective are independent from each other. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

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And p is the probability of X happening.

In this problem we have that:

n = 5, p = 0.02

What is the probability that the sample contains exactly two defective parts?

This is P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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0.38% probability that the sample contains exactly two defective parts.

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