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Answer:
The observed tumor counts for the two populations of mice are:
Type A mice = 10 * 12 = 120 counts
Type B mice = 13 * 12 = 156 counts
Step-by-step explanation:
Since type B mice are related to type A mice and given that type A mice have tumor counts that are approximately Poisson-distributed with a mean of 12, we can then assume that the mean of type A mice tumor count rate is equal to the mean of type B mice tumor count rate.
This is because the Poisson distribution can be used to approximate the the mean and variance of unknown data (type B mice count rate) using known data (type A mice tumor count rate). And the Poisson distribution gives the probability of an occurrence within a specified time interval.
Answer:
The probability that the pirate misses the captain's ship but the captain hits = 0.514
Step-by-step explanation:
Let A be the event that the captain hits the pirate ship
The probability of the captain hitting the pirate ship, P(A) = 3/5
Let B be the event that the pirate hits the captain's ship
The probability of the pirate hitting the captain's ship P(B) = 1/7
The probability of the pirate missing the captain's ship, P'(B) = 1 - P(B)
P'(B) = 1 - 1/7 = 6/7
The probability that the pirate misses the captain's ship but the captain hits = P(A) * P(B) = 3/5 * 6/7
= 0.514
Answer: 957.8
Step-by-step explanation:
Answer:
Ordering a soft drink is independent of ordering a square pizza.
Step-by-step explanation:
20% more customers order a soft drink than pizza, therefore they cannot be intertwined.
Given: P(A)=0.5 & P(B)=.7
P(A∩B) = P(A) × P(B)
= 0.5 × .7
= 0.35
P(A∪B) = P(A) + P(B) - P(A∩B)
= 0.5 + .7 - 0.35
= 0.85
P(AΔB) = P(A) + P(B) - 2P(A∩B)
= 0.5 + .7 - 2×0.35
= 0.5
P(A') = 1 - P(A)
= 1 - 0.5
= 0.5
P(B') = 1 - P(B)
= 1 - .7
= 0.3
P((A∪B)') = 1 - P(A∪B)
= 1 - 0.85
= 0.15