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2 years ago

Rob says all numbers have an even number of factors Marcia says numbers have an odd number who is correct explain

Mathematics

1 answer:

Daniel [21]2 years ago

4 0

Answer:

Step-by-step explanation:

a number that is a perfect square if it has an odd number of factors.For example 25 is a perfect square then it has odd number of factors 1,5,25. If a number is not a perfect square then it can have an even number of factors.

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What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (

aalyn [17]

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $y/x=k$ or $y=kx$

in this problem we have

the point $(5,12)$ is on the line of direct variation

Find the constant of proportionality k

$y/x=k$ -------> substitute ------> $k=12/5$

the equation is

$y=\frac{12}{5}x$

Remember that

If a point is on the line of direct variation

then

the point must satisfy the equation of direct variation

we're proceeding to verify each point

case A) point $(0,0)$

$x=0\ y=0$

Substitute the value of x and y in the direct variation equation

$0=\frac{12}{5}*0$

$0=0$ -------> is true

therefore

the point $(0,0)$ is on the line of direct variation

case B) point $(2.5,6)$

$x=2.5\ y=6$

Substitute the value of x and y in the direct variation equation

$6=\frac{12}{5}*2.5$

$6=6$ -------> is true

therefore

the point $(2.5,6)$ is on the line of direct variation

case C) point $(3,10)$

$x=3\ y=10$

Substitute the value of x and y in the direct variation equation

$10=\frac{12}{5}*3$

$10=7.2$ -------> is not true

therefore

the point $(3,10)$ is not on the line of direct variation

case D) point $(7.5,18)$

$x=7.5\ y=18$

Substitute the value of x and y in the direct variation equation

$18=\frac{12}{5}*7.5$

$18=18$ -------> is true

therefore

the point $(7.5,18)$ is on the line of direct variation

case E) point $(12.5,24)$

$x=12.5\ y=24$

Substitute the value of x and y in the direct variation equation

$24=\frac{12}{5}*12.5$

$18=30$ -------> is not true

therefore

the point $(12.5,24)$ is not on the line of direct variation

case F) point $(15,36)$

$x=15\ y=36$

Substitute the value of x and y in the direct variation equation

$36=\frac{12}{5}*15$

$36=36$ -------> is true

therefore

the point $(15,36)$ is on the line of direct variation

therefore

the answer is

$(0,0)$

$(2.5,6)$

$(7.5,18)$

$(15,36)$

5 0

2 years ago

Read 2 more answers

What are the domain and range of the function?

wel

Answer: SECOND OPTION

Step-by-step explanation:

By definition the domain is the set of value of the input (x values) shown in the table attached in the problem.

By definition the domain is the set of value of the output (y values) shown in the table attached in the problem.

Therefore, keeping the above on mind, you have:

Domain:{-2,-1,0,1,2,3}

Range:{-8,-1,0,1,8,27}

8 0

2 years ago

Read 2 more answers

Put the following equation of a line into slope-intercept form, simplifying all

lilavasa [31]

Answer:

y = x -7

Step-by-step explanation:

2x - 2y = 14

The slope intercept form is

y = mx+b where m is the slope and b is the y intercept

Subtract 2x from each side

2x - 2y -2x = -2x+14

-2y = -2x+14

Divide each side by -2

-2y/-2 = -2x/-2 +14/-2

y = x -7

The slope is 1 and the y intercept is -7

8 0

2 years ago

Read 2 more answers

At a carnival, a particular game requires the player to spin a wheel. When a child plays, the game operator allows them to conti

Bumek [7]

Answer:

(a) and (e) are not valid.

Step-by-step explanation:

a) The number of traials is not fixed. In fact, the random variable counts the total number of trials.

b) This is true, the result of each trial is independent of the others.

c) This is also true. The outcomes are failure and success.

d) This is true as well, all trials are identically distributed.

e) Since (a) is not valid, this cant be true.

4 0

2 years ago

Radium decays according to the function Q(t) = Q0e-kt where Q represents the quantity remaining after t years and k is the decay

Bingel [31]

Solve

hmmm
half life
well, 120 to 60 is half

60=120e^(-0.00043t)
solve for t
divide both sides by 120
1/2=e^(-0.00043t)
take ln of both sides
ln(1/2)=-0.00043t
divide both sides by -0.00043
ln(1/2)/-0.00043=t
t≈1611.97 years
about 1612 years

3 0

2 years ago