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Aleksandr [31]
2 years ago
14

there are 500 tickets for sale in A raffle. tickets cost $3 each, or $20 for A book of 10. All 500 tickets were sold, and $1350

was raised. How many books of 10 tickets were sold?​
Mathematics
2 answers:
KATRIN_1 [288]2 years ago
5 0

Answer:

67 books of tickets

Step-by-step explanation:

-To get this, you just divide 1,350 by 20, and you will get 67!

Marat540 [252]2 years ago
5 0

Answer:

15 booklets of 10 tickets each were sold.  

Step-by-step explanation:

We are given the following information:

Let x be the number of single tickets sold and y be the number of booklets sold.

Each booklet consist of 10 tickets.

There are total of 500 tickets.

Thus, it can be represented by the equation:

x + 10y =500

The cost of single ticket = $3

Cost of booklet = $20

Total money raised = $1,350

This, can be represented in the equation:

3x + 20y = 1350

Now, we have obtained two equation in two variable. Solving these equations, we get:

2x + 20y = 1000\\3x + 20y = 1350\\x = 350\\y = 15

Thus, 15 booklets of 10 tickets each were sold.

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Jerry's Fish Shack claims that 16% of its employees are late to work once a week. The manager surveyed 25 employees and found th
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Answer:

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:  

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z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546  

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Step-by-step explanation:

Data given and notation

n=25 represent the random sample taken

\hat p=0.2 estimated proportion  

p_o=0.16 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:  

Null hypothesis:p=0.16  

Alternative hypothesis:p \neq 0.16  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>0.546)=0.585  

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