A town has a population of 14000 and grows at 3% every year. What will be the population after 6 years, to the nearest whole num
2 answers:
This problem resembles one of a compound interest type, in which we would use the following formula:
Where:
C is the initial amount
j is the interest rate
n is the number of periods
M is the final amount
Using this same formula to solve our problem, we have:
C is the initial population
j is the annual growth rate
n is the number of years
M is the final population
OK. Let's do it...
C = 14000
j = 3% = 3/100 = 0.03
n = 6
M = ?
Making the due substitutions and performing the calculations:
M = C .
M = 14000 .
M = 14000 .
M = 14000 . 1.19
M = 16,716.7
Response: 16,717
:-)
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Answer:
January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.
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z-score:
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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
January:
The mean daily sales for January was $300 with a standard deviation of $20. On the 15th of January, the shop sold $310 of yogurt. This means, respectively, that . So
February:
The mean daily sales for February was $320 with a standard deviation of $50. On the 15th of February, the shop sold $340 of yogurt. This means, respectively, that . So
January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.
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