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Zigmanuir [339]

2 years ago

10

Nadine is going to paint her younger sister’s toy chest, including the bottom. What is the approximate surface area she will pai

nt?

1 answer:

Sidana [21]2 years ago

4 0

Answer:

Step-by-step explanation:

2LW=2(38*19)=1,444

2LH=2(38*19)=1,444

2HW=2(19*19)=722

Total: 3,610 inches squared

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The orbital period, P, of a planet and the planet's distance from the sun, a, in astronomical units is related by the formula P

anygoal [31]

Answer:

a for saturn is 9.55 astronomical units

Step-by-step explanation:

Here, we are interested in calculating the distance from the sun.

Mathematically, from the question;

P = a^3/2

29.5 = a^3/2

a = 29.5^2/3

a = [3√(29.5)]^2

a = 9.55 in astronomical units

3 0

2 years ago

Read 2 more answers

Peyton is three years younger than Justin. Matt is four times as old as Peyton. If you add together the ages of Justin, Peyton a

mestny [16]

Peyton is 28 years old

Justin is 7 years old

Matt is 4 years old

8 0

2 years ago

Read 2 more answers

A drinks company use 76.8 kg of sugar in April .How much sugar the day use each day?

Strike441 [17]

Answer:

2.56 kgs

Step-by-step explanation:

76.8kg ÷ 30 days = 2.56 kgs

4 0

2 years ago

Read 2 more answers

Summer has an offer to buy an item with a sticker price of $13,200 by paying $460 a month for 36 months. What interest rate is S

AysviL [449]

Answer:

the annual interest rate is 7.583%

Step-by-step explanation:

We are given

Summer has an offer to buy an item with a sticker price of $13,200

so, we have

P=13200

paying $460 a month for 36 months

so, we can find total amount

$A=460\times 36$

$A=16560$

Let's assume

annual interest is r

total time =36 months

so, total number of years =3

Since, it is compounded monthly

so, n=12

now, we can use formula

$A=P(1+\frac{r}{n} )^{nt}$

now, we can plug values

$16560=13200(1+\frac{r}{12} )^{36}$

now, we can solve solve for r

$(1+\frac{r}{12} )^{36}=\frac{16560}{13200}$

$r=0.07583$

So, the annual interest rate is 7.583%

6 0

2 years ago

Read 2 more answers

A major department store chain is interested in estimating the mean amount its credit card customers spent on their first visit

viva [34]

Answer: D) $\$50\pm\$11.08$

Step-by-step explanation:

As per given , we have

Sample size : n= 15

sample mean : $\overline{x}=\$50.50$

Sample standard deviation: s= $20

Since population standard deviation is unknown , so we use t-test.

Significance level for 95% confidence : $\alpha=1-0.95=0.05$

Critical t-value : $t_{n-1, \alpha/2}=t_{014,0.025}=2.145$ [Using students' t-value table]

Required 95% Confidence interval :-

$\overline{x}\pm t_{n-1, \alpha/2}\dfrac{s}{\sqrt{n}}\\\\ =\$50.50\pm(2.145)\dfrac{\$20}{\sqrt{15}}\\\\\approx \$50\pm\$11.08$

Hence, the required 95% confidence interval for the mean amount its credit card customers spent on their first visit to the chain's new store in the mall assuming that the amount spent follows a normal distribution.:

$\$50\pm\$11.08$

5 0

2 years ago