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2 years ago

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Anya found the slope of the line that passes through the points (–7, 4) and (2, –3). Her work is shown below. Let (x2, y2) be (–

7, 4) and (x1, y1) be (2, –3). m = = = The slope is . What error did she make? She simplified the denominator incorrectly. The denominator simplifies to –7. She labeled the points incorrectly. The point (–7, 4) should be (x1, y1). She used an incorrect formula. The formula should be the change in y-values with respect to the change in the x-values. She used an incorrect formula. The formula should be the sum of the x-values with respect to the sum of the y-values.

2 answers:

Zielflug [23.3K]2 years ago

8 0

C.<span>She used an incorrect formula. The formula should be the change in </span>y<span>-values with respect to the change in the </span>x<span>-values.

</span>

Kaylis [27]2 years ago

6 0

Answer:

The formula should be the change in y-values with respect to the change in the x-values.

Step-by-step explanation:

Given that slope of the line passing through two points was found as per working shown.

We are to locate the error in the method

Slope of the line passing through two points = $\frac{y_2-y_1}{x_2-x_1}$

Here (x2, y2) be (–7, 4) and (x1, y1) be (2, –3).

Hence numerator = 4-(-3) =7

and denominator = -7-2=-9

The formula should be the change in y-values with respect to the change in the x-values.

If we use this formula only we get correct slope.

But Anya used formula incorrectly.

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<u>Step-by-step explanation:</u>

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A "Sample space" is defined as the set of all the possible outcomes of an event.
Here, the given event is randomly selecting a letter from the alphabets.

Therefore, the sample space must contain all the possible alphabets that can be chosen randomly.

The sample space is the set of all the 26 alphabets in English language.

⇒ Sample space = {A,B,C,D...........,Y,Z}

⇒ 26 different outcomes.

<u>2) The probability the computer produces the first letter of your first name :</u>

Here, the required outcome is getting the first letter of your first name.

Probability = No. of required outcomes / total no. of outcomes.

For example, The name Alex Davis has the first letter of the fist name as alphabet 'A'.

∴ Probability = 1 / 26

Similarly, for any first name there is going to be any one alphabet from the 26 alphabets, thus the probability to get the first letter will be always 1 / 26.

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2 years ago

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Hello,
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2 years ago

Which expression gives the distance between the points (2,3) and 4,-3)?

OleMash [197]

Answer:

C

Step-by-step explanation:

The formula for finding the distance between 2 points (x1, y1) and (x2, y2) is

d = √[(x2 - x1)² + (y2 - y1)²]

Here (x2, y2) = (2, 3) and (x1, y1) = (4, -3)

Plugging them gives us

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2 years ago

4. Hydrocarbons in the cab of an automobile were measured during trips on the New Jersey Turnpike and trips through the Lincoln

pochemuha

Answer:

No these these result do not differ at 95% confidence level

Step-by-step explanation:

From the question we are told that

The first concentrations is $c _1= 30.0 \ g/m^3$

The second concentrations is $c _2 = 52.9 \ g/m^3$

The first sample size is $n_1 = 32$

The second sample size is $n_2 = 32$

The first standard deviation is $\sigma_1 = 30.0$

The first standard deviation is $\sigma_1 = 29.0$

The mean for Turnpike is $\= x _1 = \frac{c_1}{n} = \frac{31.4}{32} = 0.98125$

The mean for Tunnel is $\= x _2 = \frac{c_2}{n} = \frac{52.9}{32} = 1.6531$

The null hypothesis is $H_o : \mu _1 - \mu_2 = 0$

The alternative hypothesis is $H_a : \mu _1 - \mu_2 \ne 0$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} }}$

$t = \frac{0.98125 - 1.6531}{ \sqrt{\frac{30^2}{32} +\frac{29^2}{32} }}$

$t = - 0.0899$

Generally the degree of freedom is mathematically represented as

$df = 32+ 32 - 2$

$df = 62$

The significance $\alpha$ is evaluated as

$\alpha = (C - 100 )\%$

=> $\alpha = (95 - 100 )\%$

=> $\alpha =0.05$

The critical value is evaluated as

$t_c = 2 * t_{0.05 , 62}$

From the student t- distribution table

$t_{0.05, 62} = 1.67$

So

$t_c = 2 * 1.67$

=> $t_c = 3.34$

given that

$t_c > t$ we fail to reject the null hypothesis so this mean that the result do not differ

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2 years ago