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2 years ago

There are 161 calories in 28 grams you eat 9 cashews totaling 12 grams. How many cashews are in one serving

Mathematics

1 answer:

makkiz [27]2 years ago

5 0

Answer:

For every 4 grams there are 3 cashews.

12g=9. So that means there are 18 cashews in 24 grams. And like we said, there are 3 cashews in every 4 grams. So there are 21 cashews for 161 cals, equating to 28g.

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Draw a diagram that shows 1/5 times 30 equals 6. Please include a diagram

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2 years ago

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A cylinder has a base area of 28.2 m2 and a height of 3.1 m. Estimate the volume of the cylinder. A) 31 m3 B) 31 m2 Eliminate C)

Irina18 [472]

The answer can't be C or D because the unit of volume is always cubed. The formula for volume of cylinder is (pi)(r^2)(h) . The pi(r^2) part is the formula for area of a circle which is what the base of the cylinder is. Fortunately the area is already given as 28.2. Plug that into the volume formula and plug in 3.1 for the height and multiply. I get 87.42 and the answer choice B seems to be the closest option

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2 years ago

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A company manufacturing oil seals wants to establish X and R control charts on the process. There are 25 preliminary samples of

alisha [4.7K]

Answer:

A ) i) X control chart : upper limit = 50.475, lower limit = 49.825

ii) R control chart : upper limit = 1.191, lower limit = 0

Step-by-step explanation:

A) Finding the control limits

grand sample mean = 1253.75 / 25 = 50.15

mean range = 14.08 / 25 = 0.5632

Based on X control CHART

The upper control limit ( UCL ) =

grand sample mean + A2* mean range ) = 50.15 + 0.577(0.5632) = 50.475

The lower control limit (LCL)=

grand sample mean - A2 * mean range = 50.15 - 0.577(0.5632) = 49.825

Based on R control charts

The upper limit = D4 * mean range = 2.114 * 0.5632 = 1.191

The lower control limit = D3 * mean range = 0 * 0.5632 = 0

B) estimate the process mean and standard deviation

estimated process mean = 50.15 = grand sample mean

standard deviation = mean range / d2 = 0.5632 / 2.326 = 0.2421

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2 years ago

Tim has an after-school delivery service that he provides for several small retailers in town. He uses his bicycle and charges $

nlexa [21]

Answer:

Step-by-step explanation:

Given that

For delivery within $1\frac{1}2$ mi, charges = $1.25

For delivery within $1\frac{1}2$ mi - $1\frac{3}4$ mi, charges = $1.70

For delivery within $1\frac{3}4$ mi - 2 mi, charges = $2.15

and

so on.

i.e.

For delivery within 2 mi - 2 $\frac{1}4$ mi, charges = $2.60

For delivery within 2 $\frac{1}4$ mi - 2 $\frac{1}2$ mi, charges = $3.05

For delivery within 2 $\frac{1}2$ mi - 2 $\frac{3}4$ mi, charges = $3.50

For delivery within 2 $\frac{3}4$ mi - 3 mi, charges = $3.95

For delivery within 3 mi - 3 $\frac{1}4$ mi, charges = $4.40

So, every 0.25 mi or $\frac{1}4$ mi increase in distance, there is an increase of $0.45 in the charges.

It is given that there is increase of 10% in the rates.

i.e. for every 0.25 mi increase in distance, there is an increase of 0.45*1.10 = $0.495 in the charges.

The distance of $3\frac{1}8$ miles lies within the range 3 mi - 3 $\frac{1}4$ mi.

So actual charges after increase of 10%

$\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}$

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2 years ago

Automobile repair costs continue to rise with the average cost now at $367 per repair (U.S. News & World Report website, Jan

tino4ka555 [31]

Answer:

$\mu = 367$

$\sigma = 88$

a. What is the probability that the cost will be more than $450?

We are supposed to find P(x > 450)

Formula : $z=\frac{x-\mu}{\sigma}$

$z=\frac{450-367}{88}$

$z=0.9431$

Refer the z table :

P(z<0.9431)=0.8264

P(z> 0.9431)=1-P(z<0.9431)=1- 0.8264= 0.1736

Hence the probability that the cost will be more than $450 is 0.1736

b)What is the probability that the cost will be less than $250?

We are supposed to find P(x<250)

Formula : $z=\frac{x-\mu}{\sigma}$

$z=\frac{250-367}{88}$

$z=-1.3295$

Refer the z table :

P(z<-1.3295)=0.0934

Hence the probability that the cost will be less than $250 is 0.0934

c)What is the probability that the cost will be between $250 and $450?

P(250<z<450)=P(z<450)-P(z<250) = 0.8264 - 0.0934 =0.733

Hence the probability that the cost will be between $250 and $450 is 0.733

d) If the cost for your car repair is in the lower 5% of automobile repair charges, what is your cost?

p = 0.05

refer the z table

z = -1.65

Formula : $z=\frac{x-\mu}{\sigma}$

$-1.65=\frac{x-367}{88}$

$-1.65 \times 88=x-367$

$-145.2+367=x$

$221.8=x$

Hence If the cost for your car repair is in the lower 5% of automobile repair charges, so, cost is $221.8

4 0

2 years ago