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hjlf
2 years ago
11

A video-streaming Web site uses 32-bit integers to count the number of times each video has been played. In anticipation of some

videos being played more times than can be represented with 32 bits, the Web site is planning to change to 64-bit integers for the counter. Which of the following best describes the result of using 64-bit integers instead of 32-bit integers?
a) 2 times as many values can be represented. b) 32 times as many values can be represented c) 2^32 times as many values can be represented. d) 32^2 times as many values can be represented.
Computers and Technology
1 answer:
Naya [18.7K]2 years ago
8 0

Answer:

c) 2^32 times as many values can be represented.

Explanation:

It's funny, this problem comes from a real-life situation, except it wasn't really foreseen :-)  And we will encounter a similar problem in less than 20 years.

The difference in terms of storage capacity from 32-bit integers and 64-bits integers is huge.

A 32-bit integer can store (signed) numbers up to 2,147,483,647. (so over 2 BILLIONS)

A 64-bit integer can store (signed) numbers up to 9,223,372,036,854,775,807 (9 BILLIONS of BILLONS)

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yulyashka [42]

Answer:

see explaination

Explanation:

#include <stdio.h>

#include <string.h>

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struct auto_t scan_auto(char *);

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char day[2];

char month[2];

char year[4];

};

struct tank_t {

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char currentFuelLevel[10];

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struct auto_t {

char make[50];

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struct date_t manufactureDate;

struct date_t purchaseDate;

struct tank_t gasTank;

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int main(int argc, char *argv[]) {

/* the first command-line parameter is in argv[1]

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FILE *fp = fopen(argv[1], "r"); /* "r" = open for reading */

char buff[BUFSIZE]; /* a buffer to hold what you read in */

struct auto_t newAuto;

/* read in one line, up to BUFSIZE-1 in length */

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/* buff has one line of the file, do with it what you will... */

newAuto = scan_auto(buff);

printf("%s\n", newAuto.make);

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fclose(fp); /* close the file */

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struct auto_t scan_auto(char *line) {

int spacesCount = 0;

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for (i = 0; i < sizeof(line); i++) {

if (line[i] == ' ') {

spacesCount++;

if (spacesCount == 1) {

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}

else if (spacesCount == 2) {

endOfModel = i;

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else if (spacesCount == 3) {

endOfOdometer = i;

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newAuto.model[count++] = line[i];

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newAuto.model[count] = '\0';

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8 0
2 years ago
Which of the following is ideal for long distance communication ?
Vinvika [58]
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3 0
2 years ago
If Maya wants to access a view that would control multiple slides within a presentation, which view should she utilize? Master v
Basile [38]

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6 0
2 years ago
Use the loop invariant (I) to show that the code below correctly computes the product of all elements in an array A of n integer
NeTakaya

Answer:

Given Loop Variant P = a[0], a[1] ... a[i]

It is product of n terms in array

Explanation:

The Basic Step: i = 0, loop invariant p=a[0], it is true because of 'p' initialized as a[0].

Induction Step: Assume that for i = n - 3, loop invariant p is product of a[0], a[1], a[2] .... a[n - 3].

So, after that multiply a[n - 2] with p, i.e P = a[0], a[1], a[2] .... a[n - 3].a[n - 2].

After execution of while loop, loop variant p becomes: P = a[0], a[1], a[2] .... a[n -3].a[n -2].

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And multiply a[n-1] with p, i.e P = a[0].a[1].a[2].... a[n-2].

a[n-1]. i.e. P=P.a[n-1]

By the assumption for i=n-3 loop invariant is true, therefore for i=n-2 also it is true.

By induction method proved that for all n > = 1 Code will return product of n array elements.

While loop check the condition i < n - 1. therefore the conditional statement is n - i > 1

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6 0
2 years ago
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Marat540 [252]
The correct option is D; STYLES PANE.
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3 0
2 years ago
Read 2 more answers
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