Answer:
78% probability that a randomly selected online customer does not live within 50 miles of a physical store.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this problem, we have that:
Total outcomes:
100 customers
Desired outcomes:
A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical stores. So the number of desired outcomes is 78 customers.
Using this estimate, what is the probability that a randomly selected online customer does not live within 50 miles of a physical store?
78% probability that a randomly selected online customer does not live within 50 miles of a physical store.
Answer:
F
Step-by-step explanation:
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Answer and Step-by-step explanation:
Data provided in the question
Mean = 1.1 hours per call =
R = Mean rate = 1.6 per eight hour day
= 
= 5 per day
Based on the above information
a. The average number of customers is
= 151
b. The system utilization is
= 
= 0.32
c. The amount of time required is
= 1 - system utilization
= 1 - 0.32
= 0.68
And, there is 8 hours per day
So, it would be
= 
= 5.44 hours
d. Now the probability of two or more customers is
= 0.1024
Therefore we simply applied the above formulas
Answer:
a for saturn is 9.55 astronomical units
Step-by-step explanation:
Here, we are interested in calculating the distance from the sun.
Mathematically, from the question;
P = a^3/2
29.5 = a^3/2
a = 29.5^2/3
a = [3√(29.5)]^2
a = 9.55 in astronomical units
Let's use 8 days as the maximum time we are going to be renting the car.
Putting that into the equation means, 500$ for Harry's Rentals and Smilin' Sam's at $600.
Therefore, Happy Harry's Rentals are better for the 7th and 8th days while Smiling Sam's are the better from day's 1 to 6.
Work:
500$ is a fixed value so it doesn't change (constant)
200 + 50x
x = days
8 days = 8x
200 + 50(8)
200 + 400 = 600
