Answer:
C
Explanation:
The production of ATP is greatest at 50o C as indicates by the production of CO2 in the Krebs Cycle
Answer:
The correct answers are: Ribosome, Mitochondria, Chloroplast (in case of a plant cell).
Explanation:
- The Endo-membrane system in the cell represents the membranes of the Nucleus, Endoplasmic Reticulum, Golgi apparatus, Plasma Membrane, Vacuole and Lysosome.
- The Nuclear Envelope is made up of a phospholipid bilayer which remains in continuation with the ER (endoplasmic reticulum) membrane.
- Therefore, fluorescent tagged integral membrane protein localised in the outer nuclear envelope can move into the ER membrane by lateral movement or through vesicles that bud off from the membrane of the nuclear envelope and fuse with that of the ER membrane.
- Vesicles bud off from the membrane of the ER and fuse with the Golgi apparatus. Therefore, the fluorescent tagged integral membrane protein can move into the membrane of the Golgi apparatus.
- Vesicles bud off from the Golgi apparatus and fuse with the Plasma membrane, Lysosome membrane, and Vacuole membrane. Hence, the fluorescent tagged integral membrane protein can be found in all these organelles.
- Ribosome lacks a membrane and hence, the fluorescent tagged integral membrane protein will be absent over here.
- Both Mitochondria and Chloroplast, are self-replicating and dividing organelles. Their proteins (membrane or matrix) are encoded mostly by their own genome. Also, vesicles that bud from from nucleus or ER or Golgi apparatus do not fuse into their membrane. Hence, the fluorescent tagged protein would not be able to reach their membrane.
I believe the answer is the B-cell
These are types of lymphocyte derived from the bone marrow and provides the humoral immunity. They produce antibodies; which are proteins that sticks to pathogen preventing them from sticking to cells and flagging them for destruction. The primary role of the B-cells is to make antibodies in large amounts and assist in destroying foreign agents through role as APC.
Answer:
Bull = Pp
Cow A = pp
Cow B = pp
Cow C = Pp
Explanation:
In cows polled (P) is dominant over horned (p) trait.
The bull is polled so it can be PP or Pp. Cow B is horned so it must be pp. Resultant offspring from bull X Cow B is also a horned calf (pp). This calf must have received one p from the bull. So the bull's genotype is Pp.
Cow A is also a horned cow so it must be pp. When bull X Cow A, a polled calf is produced. Since the bull's genotype is Pp and Cow A's genotype is pp, this polled calf will be Pp like the bull.
Cow C is polled like the bull so it can be PP or Pp. However on crossing with the bull (Pp) a horned calf is produced (pp). This calf got one p allele from the bull and p allele from the Cow C. So Cow C's genotype must be Pp.
Hence,
Bull = Pp
Cow A = pp
Cow B = pp
Cow C = Pp
