Ask question

Ask question

All categories

2 years ago

12

Pls help i have a test tmrw and i don't understand anything

1 answer:

Alex777 [14]2 years ago

3 0

Answer:

Step-by-step explanation:

Go on super teacher worksheets to get the answer key

You might be interested in

Jessie runs four days a week after school She

Usimov [2.4K]

Answer:

she runs 8 miles on Monday 8 miles on Wednesday 8 miles on Thursday and 5 miles on Friday

Step-by-step explanation:

8+8+8+5 = 29

3 0

2 years ago

Find the simplified product b-5/2b x b^2+3b/b-5

White raven [17]

Answer:

The product $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}$

Step-by-step explanation:

Given expression $\frac{b-5}{2b}$ and $\frac{b^2+3b}{b-5}$

We have to find the product of $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}$

Consider the given expression $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}$

Multiply fractions, we have,

$\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}$

$=\frac{\left(b-5\right)\left(b^2+3b\right)}{2b\left(b-5\right)}$

Cancel common factor ( b - 5 )

we have, $=\frac{b^2+3b}{2b}$

Apply exponent rule,

$\:a^{b+c}=a^ba^c$

$b^2=bb$

$=bb+3b=b(b+3)$

$=\frac{b\left(b+3\right)}{2b}$

Cancel common factor b , we have,

$=\frac{b+3}{2}$

Thus, the product $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}$

8 0

2 years ago

Read 2 more answers

The graph of the function f is shown. f(3) =

STALIN [3.7K]

Draw a picture! 29) The graph of the function f is shown<span> to the right. y Which of the following statements is false? ... </span>3<span>) On </span>the graph<span> to the right, draw a </span>function<span> that has the following properties: 0 A step (or jump) discontinuity at x = 5 </span>

6 0

2 years ago

Read 2 more answers

3 freshmen and 2 sophomores from a sorority will attend a conference. If the sorority has 12 freshmen and 9 sophomores, in how m

padilas [110]

Answer:

7920

Step-by-step explanation:

12C3 × 9C2

= 220×36

= 7920

3 0

2 years ago

Read 2 more answers

12x+7<−11 AND5x−8≥4012

Arte-miy333 [17]

Answer:

No solution

Step-by-step explanation:

Given: $12x+7$ and $5x-8\geq 40$

Solve both inequality separately.

$12x+7$ Subtraction property of inequality

$12x$

$12x$

$x$

$x$

and

$5x-8\geq 40$ Addition property of inequality

$5x\geq 40+8$

$5x\geq 48$

$x\geq \dfrac{48}{5}$

Hence, the solution of the compound inequality intersection of both solutions.

Please find attachment for number line solution.

No solution

8 0

2 years ago

Read 2 more answers