A supermarket shop cans display consists of 5 levels of stacked cans. In the display, each level has 4 more cans than the level above it-the total number of cans in display are (b) 100
Step-by-step explanation:
Given that ,
The display consists of 5 levels of stacked cans- <u>which means that there are 5 levels in which the stacked cans are displayed .</u>
so,the no:of levels are 5
Now given that level has 4 more cans than the level above it.
so. the number of cans in a single level = 5*4=20
Now we know that the total number of level is 5 so we multiply 20 withe the number of levels of can stacked
==>20*5=100
<u>Thus we can say that the total number of cans in display are (b) 100</u>
Let's convert the task into an example, simplifyng which will make us able to get the answer.
So, according to the task:
![\sqrt[9]{x} * \sqrt[9]{x} * \sqrt[9]{x} * \sqrt[9]{x} = \sqrt[1/ 9 ]{x} * \sqrt[1/9]{x} * \sqrt[1/9]{x} * \sqrt[1/9]{x}](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B9%5D%7Bx%7D%20%0A%0A%3D%20%20%20%5Csqrt%5B1%2F%209%20%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20)
Now we can simplify:
![\sqrt[1/9]{x} + 1/9+1/9+1/9 = x^{4/9}](https://tex.z-dn.net/?f=%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20%2B%201%2F9%2B1%2F9%2B1%2F9%0A%0A%3D%20x%5E%7B4%2F9%7D%20)
So the answer is <span>
C:x to the four ninths power</span>
Answer:
The Answer is B
Step-by-step explanation:
Edgenuity ;)
Answer:
6 cm
Step-by-step explanation:
If the linear scale factor of two solids is k, then the volume scale factor is k^3.
The volume scale factor is 128/54 = 64/27 = (4/3)^3.
The linear scale factor is 4/3.
4.5 cm * 4/3 = 6 cm
Answer: The height of the larger container is 6 cm.
Answer:
A) ∃y(¬P(y))
B) ∀y(P(y) ^ Q(y))
C) ∀y(P(y) ^ Q(y))
D) ¬∃y(P(y) ^ Q(y))
E) ∃y(¬P(y) ^ Q(y))
Step-by-step explanation:
We will use the following symbols to answer the question;
∀ means for all
∃ means there exists
¬ means "not"
^ means "and"
A) Something(y) is not in the correct place is represented by;
∃y(¬P(y))
B) For All tools are in the correct place and are in excellent condition, let all tools in the correct place be P(y) and let all tools in excellent condition be Q(y).
Thus, we have;
∀y(P(y) ^ Q(y))
C) Similar to B above;
∀y(P(y) ^ Q(y))
D) For Nothing is in the correct place and is in excellent condition:
It can be expressed as;
¬∃y(P(y) ^ Q(y))
E) For One of your tools is not in the correct place, but it is in excellent condition:
It can be expressed as;
∃y(¬P(y) ^ Q(y))