In a train yard, there are 6 flat cars, 7 boxcars, and 3 livestock cars. A train is made up of 9 cars. Which would you use to fi
2 answers:
Answer:
Option A
Step-by-step explanation:
In a train yard there are 6 flat cars, 7 box-cars and 3 livestock cars.
So total number of cars = 6 + 7 + 3
= 16
Now a train is to be made by 9 cars, out of 16 cars.
So number of ways the train can be made up will be =
where n = 16 and r = 9
so number of ways =
Option A is the answer.
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Answer:
A and C
Step-by-step explanation:
To determine which events are equal, we explicitly define the elements in each set builder.
For event A
A={1.3}
for event B
B={x|x is a number on a die}
The possible numbers on a die are 1,2,3,4,5 and 6. Hence event B is computed as
B={1,2,3,4,5,6}
for event C
Hence the set c is C={1,3}
and for the set D {x| x is the number of heads when six coins re tossed }
In the tossing a six coins it is possible not to have any head and it is possible to have head ranging from 1 to 6
Hence the set D can be expressed as
D={0,1,2,3,4,5,6}
In conclusion, when all the set are compared only set A and set C are equal