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1 year ago

What is the value of m in the figure below? If necessary,round your answer to the nearest tenth of a unit

Mathematics

1 answer:

bogdanovich [222]1 year ago

3 0

Answer:

Step-by-step explanation:

It turns out from similar triangles, that 7/BD = BD / 18. Use triangles ABD and BDC to show this relationship. Solving this equation will give you BD

BD^2 = 7*18

BD^2 = 126 Just leave it in this form. Do your rounding at the end.

Because triangle BDC is a right angle triangle, use the Pythagorean Theorem to solve for m

m^2 = BD^2 + 7^2

m^2 = 126 + 49

m^2 = 175 Take the square root of both sides.

sqrt(m^2) = sqrt(175)

m = 13.22

so the answer is D

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Atley, Bradley, Cursen, and Drake are the married names of Kermit, Leonard, Marlene, and Norma. Read the clues to find each pers

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This is how the chart will look like:
Kermit Leonard Marlene Norma
Atley

Bradley

Cursen

Drake

1. Drake is Bradley's sister.
2. Cursen is Atley's brother
3. Norma and Drake are not related
<span>4. Kermit is a year older than Bradley
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Drake is a girl (1), but she is not related to Norma(3), So she is Marlene.
1) MARLENE DRAKE

Drake and Bradley are related; Norma is not related to them(3). Norma can either be Atley or Cursen. But, Cursen is Male. So, Norma is NORMA ATLEY

Remaining family names are Bradley and Cursen. Kermit is not a Bradley, so he is KERMIT CURSEN. That leaves LEONARD BRADLEY.

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1 year ago

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hury!!!! Which system is equivalent to StartLayout Enlarged left-brace 1st row y = negative 2 x squared 2nd row y = x minus 2 En

jeka57 [31]

Answer:

3rd Option

Step-by-step explanation:

Which equation is the inverse of y = 7x2 – 10?

y = StartFraction plus-or-minus StartRoot x + 10 EndRoot Over 7 EndFraction

y = plus-or-minus StartRoot StartFraction x + 10 Over 7 EndFraction EndRoot

x = plus-or-minus StartRoot StartFraction x Over 7 EndFraction + 10 EndRoot

y = StartFraction plus-or-minus StartRoot x EndRoot Over 7 EndFraction plus-or-minus StartFraction StartRoot 10 EndRoot Over 7 EndFraction

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Evaluate 4-0.25g+0.5h4−0.25g+0.5h4, minus, 0, point, 25, g, plus, 0, point, 5, h when g=10g=10g, equals, 10 and h=5h=5h, equals,

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I believe the correct given equation is in the form of:

4 – 0.25 g + 0.5 h

Now we are to evaluate the equation with the given values:

g = 10 and h = 5

What this actually means is that to evaluate simply means to calculate for the value of the equation by plugging in the values of the variables. Therefore:

4 – 0.25 g + 0.5 h = 4 – 0.25 (10) + 0.5 (5)

4 – 0.25 g + 0.5 h = 4 – 2.5 + 2.5

4 – 0.25 g + 0.5 h = 4

Therefore the value of the equation is:

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Original-drank+added=result

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A. see above

B. addition and subtraction facts

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When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal. During one

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Answer:

0.82 = 82% probability that at least one party will not order drinks

Step-by-step explanation:

For each party, there are only two possible outcomes. Either they will order drinks with their meal, or they will not. The probability of a party ordering drinks with their meal is independent of other parties. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal.

This means that $p = 0.75$

During one hour, Ryan served 6 parties. Assuming that each party is equally likely to order drinks, what is the probability that at least one party will not order drinks?

6 parties, so n = 6.

Either all parties will order drinks, or at least one will not. The sum of the probabilities of these events is decimal 1. So

$P(X = 6) + P(X < 6) = 1$