Answer:
2(8x^2-13x+10)
Explanation:
There are 5 angle s in a pentagon and we are assuming are pentagon is a regular one so the angles are all congruent.
Let's let A represent the measurement of one of the those angles in our pentagon.
The sum of our angles in our pentagon would then be A+A+A+A+A or 5A.
But we are also given that this equals 40x^2-65x+50.
So that means 5A=40x^2-65x+50.
If we divide both sides by 5 we can find what one of our angles is in terms of x. So let's do that A=8x^2-13x+10.
So we want to know the sum of two our angles, we want to know what is A+A or 2A. 2A=2(8x^2-13x+10). To obtain that I just multiplied both sides of A=8x^2-13x+10 by 2.
