1.2 pH is a on a scale where the lower the number, the higher the acidity.
The answer is <span>C.silent.
Nonsense, missense, silent, and frameshift mutations are point mutations. The point mutations are the change in a single nucleotide base on the DNA molecule. In a missense mutation, the change in a single nucleotide base results in a codon coding for a different amino acid. In a nonsense mutation, the change in a single nucleotide results in a stop codon or in a nonsense codon. Frameshift mutation, due to addition or deletion of a base, results in the change of reading frame and totally different translation. In all these cases, the change could lead to different of nonfunctional protein translation.
Silent mutation, on the other, means that change in a nucleotide base will no affect amino acid. It will result in a different codon, but the one that code for the same amino acid, so the same protein will be produced.
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<u>ANSWER:</u>
The correct option is B- Qualitative.
<u>EXPLANATION:</u>
When the growth of corn has to be recorded, the quality of the corn grown in different soils needs to be recorded. Qualitative methods are best used to classify quality of anything.
Qualitative data basically is non-numerical data which in the case of corns can be the length of the corn plant, the sweetness of the corn kernel or the hardness or softness of the corn. This data cannot be recorded using numerical values and so other methods of data recording cannot be used.
Answer:
The correct answer is option C.
Explanation:
The Chondrichthyes is a class that comprises the cartilaginous fishes such as batoids, ratfish, sharks and others, The Chondrichthyes and the Osteichthyes also known as bony fish were distinguished in early classification but it was not clear at that time when bony skeletons appeared in the vertebrates.
Traces of bone tissues that are found in fossil and living Chondrichthyes are suggested that these cartilaginous fishes derived after the origin of the bony skeleton in vertebrates.
Thus, the correct answer is option C.
The answer is D) 1/2.
If each allele confers a unit of color darkness, then only genotypes S2S3 and S1S4 will have 5 units of color darkness because in genotype S2S3 S2 will have 2 units, and S3 will have 3 units, which is 5 units in total. The similar math is for <span>genotypes S1S4.
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Now, let's cross S1S3 and S2S4:
Parents: S1S3 x S2S4
Offspring: S1S2 S1S4 S2S3 S3S4
The offspring with genotype S1S2 will have 3 units of color darkness. The offspring with genotype S1S4 will have 5 units, as well as the offspring with genotype S2S3. The <span>offspring with genotype S3S4 will have 7 units.
It can be assumed that only 2 genotypes out of 4 will have 5 units:
2/4 = 1/2.</span>
