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PtichkaEL [24]
2 years ago
15

In a sample of 2,400 people, 1,482 were found to have the dominant (taster) phenotype. Assuming that the population is in Hardy-

Weinberg equilibrium, approximately how many individuals in the sample are expected to be heterozygous for TAS2R38?
Biology
1 answer:
Alex_Xolod [135]2 years ago
5 0

Answer:

1128.

Explanation:

The dominant taster phenotype is 1482.

The recessive taster phenotype = 2400 – 1482 = 918 .

Recessive phenotypes = 2400 – 1482 = 918

The recessive phenotype frequency = q² = 918 / 2400 = 0.38.

the recessive allele frequency q = √0.38 = 0.62.

The dominant allele frequency, p = 1-q = 1- 0.62 = 0.38

The heterozygous frequency =  2pq = 2 ×0.38 × 0.62 = 0.47 .

The heterozygous individual in the population = 0.47 × 2400 = 1128.

Thus, the answer is 1128.

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Hello. This question is incomplete. Also, you forgot to show the flowchart. The flowchart is attached below and the full question is:

The flowchart below shows the three generations of a cross between a pea plant that has yellow pods and a pea plant that has green pods. Green pods are the dominant trait. The flowchart is missing the labels that describe the traits.

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3.A,C and D

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As shown in the question above, the flowchart shows the crossing of a pea plant with dominant features (green pods - AA) and a pea plant with recessive features (yellow features - aa). The crossing between plants with AA and aa alleles generates a completely Aa population, which in this case, has the dominant characteristic, that is, it has green pods. This is because the "Aa" alleles are called heterozygous and develop the dominant characteristic.

As we can see in the flowchart, the crossing between the two pea plants generated an offspring that is identified by table C, as we know this offspring has green pods and in the flowchart it is represented by a grayish rectangle. Therefore, we can say that the other gray rectangles represent pea plants with green pods, which are rectangles A, C and D.

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Answer:

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Explanation:

The eye color and bristle size is coordinated by either recessive cn and dominant CN or Cn genes. The wild type in questions has red color eyes, which is a dominant trait coordinated by CN or Cn if c and n can undergo assortment independently or just CN if they cannot. The second characteristics of the wild type is long bristle. We were told that reduced bristle is coordinated by recessive rd Gene. Then the long bristle in our specimen wild type will have dominant genotypic notification of RD or Rd, depending if r and d can undergo assortment independently. The last trait is a round eyes, which is a recessive trait controlled by recessive allele l. Therefore, the combined characteristics of red eye color, long bristle and round eyes shape of the wild type will be CNRDl or any of CNRDll, CnRdl, CnRDl CNRdl depending on the segregation pattern of c, n, r and d.

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