Question

Consider a cross of beetles with exoskeleton alleles B and b and leg size alleles N and n. The maleparent is heterozygous in both traits. The female parent is homozygous recessive in both traits.a.Write the four letter genotype for each parent.b.Use the Punnet square below to find the possible allele combinations for an offspring.Possible allele combinations from the maleBNBnbNbnPossible allelecombinationsfrom the femalebnBbNnBbnnbbNnbbnnbnBbNBbnnbbNnbbnnbnBbNnBbnnbbNnbbnnbnBbNnBbnnbbNnbbnnc.What is the probability that the offspring will have a genotype of Bbnn?4/16d.Show how statistics could be used to calculate the probability you found in part c withoutusing a Punnett square.

Answer 1

Answer:

a. Genotype of male parent= BbNn

Genotype of female parent: bbnn

b: Progeny ratio= 1: 1: 1: 1

c: 1/4

Explanation:

a. Genotype of male parent= BbNn

Genotype of female parent: bbnn

b. Gamete formed by the male parent: BN: Bn: bN: bn in 1:1:1:1 ratio.

Gametes formed by female parent: All gametes with "bn" alleles.

c.  The probability that the offspring will have a genotype of Bbnn=

Bb x bb= 1/2 Bb: 1/2 bb

Nn x nn= 1/2 Nn: 1/2 nn

Therefore, probability that the offspring will have a genotype of Bbnn= 1/2 Bb x 1/2 nn= 1/2.