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Zinaida [17]
1 year ago
10

What percentage of birds with the most common beak depth in 1976 survived the drought?

Biology
2 answers:
Taya2010 [7]1 year ago
7 0

Answer:

the sample of 200 medium ground finches measured in 1976 (Figure 1). The number of individuals has increased to close to the number of birds present in the population before the drought. However, the most common beak depth has increased from 8.8 mm to 9.8 mm .

ANTONII [103]1 year ago
5 0
Hi!

The answer is About 6%

Hope this helps !
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Threonine is a standard amino acid with a polar side chain.Identify the chiral centers in threonine. a. the carboxyl carbon b. t
luda_lava [24]

Answer:

Threonine has two chiral centers.

The correct options are c. carbon b and d. carbon c

Explanation:

Chiral centers are those that have four different groups of atoms bonded to it. Carbon a has three atoms of hydrogen attached to it so it can't be a chiral carbon. It isn't the carboxyl carbon either since it is double bonded to oxygen. And the amino nitrogen does not qualify anyway because it is bonded to three different groups of atoms, not four.

6 0
1 year ago
Explain the relationship among
Iteru [2.4K]

Answer:

There is an important relationship among  homeostasis, defective mitochondria, and the  symptoms caused by LHON.

Explanation:

There is a great relationship among  homeostasis, defective mitochondria and the  symptoms caused by LHON because defective mitochondria disturbs the homeostasis in the body. If mitochondria works properly, homeostasis will be maintained whereas if there is any defect occurs in the mitochondria then the whole homeostasis will be adversely affected because mitochondria is the powerhouse of the cell responsible for the production of energy for the cell. Symptoms occurs due to Leber's hereditary optic neuropathy (LHON) also effected the state of equilibrium in the body.

6 0
1 year ago
Mendel performs a cross using a true-breeding pea plant with round, yellow seeds and a true-breeding pea plant with green, wrink
timama [110]

Answer:

F1 Generation -

Genotype - GgRr

Phenotype - Green and round

F2 generation -

Genotype Ratio –  

GGRR: GGRr: GgRR: GgRr: GGrr: Ggrr: ggRR: ggRr: ggrr

1:2:2:4:1:2:1:2:1

Phenotypic ration  

Green & round: Green & wrinkled: yellow & round:yellow : wrinkled

9: 3:3:1

Explanation:

G represents Green seed color

g represents yellow seed color

R represents round seed

r represents wrinkled seed

Here G is dominant over g and R is dominant over r

F1 generation -

Genotype of true breeding parents will be

GGRR and ggrr

The offspring produced will be -

GgRr

Genotype - GgRr

Phenotype - Green and round

F2 Generation -

Genotype Ratio –  

GGRR: GGRr: GgRR: GgRr: GGrr: Ggrr: ggRR: ggRr: ggrr

1:2:2:4:1:2:1:2:1

Phenotypic ration  

Green & round: Green & wrinkled: yellow & round:yellow : wrinkled

9: 3:3:1

8 0
1 year ago
If you measured an entire bar of soap and compared it to the piece of soap from this activity, would the bar and the piece have
Ray Of Light [21]

Answer:

Different mass

Different volume

Same density

Explanation:

Intensive physical properties are those properties of a substance that is not dependent on amount i.e. do not change in response to changes in the amount of the substance. Intensive properties include density, temperature, boiling point etc.

On the other hand, extensive properties are those properties that are dependent on the amount of the substance. For example, mass and volume are extensive properties.

Hence, according to this question, measuring an entire bar of soap and comparing it to a piece of soap, the bar and the piece would have a:

- Different mass ( size dependent)

- Different volume (size dependent)

- Same density (size independent)

4 0
1 year ago
Consider a population of frogs. Allele B1 codes for spotted frogs; allele B2 codes for non-spotted frogs. B1 is dominant to B2 .
oee [108]

Answer:

Frequency of B1 = 0.47

Frequency of B2 = 0.53

Hope this helps!

4 0
2 years ago
Read 2 more answers
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